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Whitepunk [10]
3 years ago
6

The moon is about 240,000 miles from earth what is the distance right reading as a whole number multiplied by a power of 10

Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0
Its 240,000 times its self ten times here is how it is



240,000
240,000
240,000
240,000
240,000
×
240,000
240,000
240,000
240,000
240,000
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If x = -2, what does -x mean
pickupchik [31]

Answer:

<h2><em><u>-x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em></h2>

Step-by-step explanation:

<em><u>If</u></em><em><u>,</u></em>

x = -2

<em><u>Then</u></em><em><u>,</u></em>

-x = -(-2)

=> <em><u>-x = 2 (Ans)</u></em>

6 0
3 years ago
Solve the triangle. Round your answers to the nearest tenth.
wel

Answer:

m∠A ≈ 43°

m∠B ≈ 55°

mBC ≈ 20

Step-by-step explanation:

Law of Sines: \frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Step 1: Find m∠B

\frac{29}{sin82} =\frac{24}{sinB}

Step 2: Solve for ∠B

29sinB = 24sin82°

sinB = 24sin82°/29

B = sin⁻¹(24sin82°/29)

B = 55.038°

Step 3: Find m∠A

180 - (55.038 + 82)

180 - 137.038

m∠A = 42.962°

Step 4: Find BC

\frac{29}{sin82} =\frac{BC}{sin42.962}

Step 5: Solve for BC

29sin42.962° = BCsin82°

BC = 29sin42.962°/sin82°

BC = 19.9581

4 0
2 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
How could you use coordinate geometry to prove that segment BC is congruent to segment AD?
liberstina [14]

Answer:

  Prove the lengths are the same

Step-by-step explanation:

When we say segments are congruent, we mean their lengths are the same.

__

Let's see if they are congruent.

  AD = √((3-(-3))² +(2-2)²) = 6

  BC = √((6-0)² +(6-6)²) = 6

AD ≅ BC . . . . their lengths are the same

8 0
2 years ago
Read 2 more answers
Approximate the value of 13√ to the nearest tenths place. Plot the approximation on the number line.
aalyn [17]
The square root of 13 rounded to the nearest tenth is 3.6, so you would plot this somewhere in between 3 and 4 on a number line.
4 0
2 years ago
Read 2 more answers
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