The moon is about 240,000 miles from earth what is the distance right reading as a whole number multiplied by a power of 10

1 answer:

4 0

Its 240,000 times its self ten times here is how it is

240,000
240,000
240,000
240,000
240,000
×
240,000
240,000
240,000
240,000
240,000

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Using the slope formula, determine the slope of the two points.

Lelechka [254]

The slope formula is is rise over run or y2-y1/x2-x1

If you plug in those numbers you will get

(-1)-(-4)
———
1-(-2)

Simplify it and you get

3
— or 1
3

So the slope is 1

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What is the rate of A, what is the rate of B, which equation has a greater rate?

11Alexandr11 [23.1K]

Answer: Rate of A: 5/6

Rate of B: 3/5

A has a higher rate of change

Step-by-step explanation: You calculate slope/rate of change by determining the rise over the run. The rate of change in A is 5/6x, this is bigger than the slope of B.

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Why is looking at cash flow an important step in a good financial plan

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3 years ago

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a brownie recipe calls for 1 cup of sugar and 1/2 cup of flour to make one batch of brownies. To make multiple batches, the equa

Lady_Fox [76]

Answer:

Step-by-step explanation:

f = 1/2s

Let s = 2 that means f = 1 That means for 2 cups of sugar there is 1 cup of flour.

This point must be on the graph

It is on A, not on B, not on C

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3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

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