Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
Answer:
R2 = 6.44
T2 = 8.82
Whole = 30.42
Step-by-step explanation:
R1 = 2.8 X 3.1
T1 = (1/2) X (2.4) X (5.4)
R2 = (5.4-3.1) X (2.8) = 6.44
T2 = (1/2) X (11.7-5.4) X (2.8) = 8.82
Whole = (1/2) X (11.7) X (2.4+2.8) = 30.42
Hi yes what do u need help with??
<span>Best you can do is describe a set:
John
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