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3 years ago

Do all rectangles have four congruent sides? Explain.

2 answers:

6 0

for a rectangle to be a rectangle, it must always have all interior angles of 90° each, and therefore by definition, they'll all be congruent.

Naddik [55]3 years ago

4 0

Answer:

Yes they all do

Step-by-step explanation:

All rectangles have 4 congruent sides because rectangles are quadralateral

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Round 8326 to the nearest hundred. Enter your answer in the box below

riadik2000 [5.3K]

Answer:

8330 is your answer.

Step-by-step explanation:

So the hundred's place is the 2.

To round you have to look at the number behind you.

6 is behind 2 and it is greater than 5 so you round up.

8330 is your answer.

5 0

4 years ago

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What is the first term in this expansion? a 2x15 b 215x15 c 10y15 d 1015y15

Oduvanchick [21]

Answer:

2^15x^15 is the correct answer.

Step-by-step explanation:

8 0

3 years ago

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Help with this algebra question

choli [55]

If two lines are perpendicular, the slope of one of the lines is the negative reciprocal of the other. Since we know the slope for one of our lines, $2$ m lets find the other:
$m=- \frac{1}{2}$

Now, lets use the point-slope formula to complete the equation of our perpendicular line:
$y-y_{1}=m(x-x_{1})$
$y-5=- \frac{1}{2} (x-2)$
$y-5=- \frac{1}{2}x+1$
$y=- \frac{1}{2} x+6$

We can conclude that our perpendicular line is $y=- \frac{1}{2} x+6$

3 0

4 years ago

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9. A band director wants to form a committee of 4 parents from a list of 45 band parents.

Alex73 [517]

Answer:

Part (A): The number of ways to select 12 jurors are 86493225.

Part (B): The number of ways to select 2 alternates are 306.

Part (C): Part (a) is an example of combination and Part (a) is an example of permutation

Step-by-step explanation:

Consider the provided information.

A band director wants to form a committee of 4 parents from a list of 45 band parents.

Part (A): How many different groups of 4 parents can the band director select?

Since order doesn't matter so we will use combination.

Use the formula for combination $^{n}C_{r}=\frac{n!}{r!(n-r)!}$

Substitute n=45 and r=4 in above formula.

$^{45}C_{4}=\frac{45!}{4!(45-4)!}$

$^{45}C_{4}=\frac{45!}{4!41!}$

$^{45}C_{4}=148995$

Hence, the number of ways are 148995.

Part (B) How many different ways can the band director select 4 parents to serve in the band parents’ association as president, vice president, treasurer, and secretary?

Since the order matter so we will use permutation:

The formula for permutation is: $^{n}P_{r}=\frac{n!}{(n-r)!}$