Answer:
3.3.14259265359 re-uccering
Step-by-step explanation:
Answer:
a) The car will be worth $8000 after 2.9 years.
b) The car will be worth $6000 after 4.2 years.
c) The car will be worth $1000 after 12.7 years.
Step-by-step explanation:
The value of the car after t years is given by:

According to the model, when will the car be worth V(t)?
We have to find t for the given value of V(t). So





(a) $8000
V(t) = 8000

The car will be worth $8000 after 2.9 years.
(b) $6000
V(t) = 6000

The car will be worth $6000 after 4.2 years.
(c) $1000
V(t) = 1000

The car will be worth $1000 after 12.7 years.
Answer:
The amount that must be deposited is $ 19973.87.
Step-by-step explanation:
We have a relation between future value present value as:
F= P 
F=future value
P=present value
r=rate (as a decimal)
n=number of compounding periods per year
t=number of years
Now,
assume rate as 8%
35000= P 
or, 35000= P × 
or, P = 
or, P = $ 19973.87
So you must deposit $ 19973.87 today.
(60x2)+30 = 150 miles
30 = 1/2 of 60 which is half an inch
60 x2 because he travels 2 inches
The area of a trapezoid is the average of the bases times the height, mathematically:
A=h(b1+b2)/2, in this case:
A=3(1.25ft(12in/ft)+14)/2
A=3(29)/2
A=43.5 in^2