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KatRina [158]
4 years ago
15

Word bank: (Thermosphere) (Aurora boreal is) ( Large-scale air turbulence and mixing at this layer) ( Stratosphere) (The coldest

temperatures in the atmosphere occur at the junction) (Maximum ozone)
Biology
1 answer:
Lyrx [107]4 years ago
5 0
  • Thermosphere - Fourth layer of Earth's atmosphere.
  • Aurora Borealis - Ionosphere layer of thermosphere.
  • Large-scale air turbulence and mixing at this layer - Troposphere
  • Stratosphere - Second lowest layer of Earth's atmosphere. No Air turbulence so airplanes fly in this layer.
  • The coldest temperatures in the atmosphere occur at the junction- of Stratosphere and mesosphere
  • Maximum ozone - Ozone layer in Stratosphere

Explanation:

Atmosphere is formed by mixing of gases. The layers of atmosphere is given below.

1. Troposphere -

  • The first layer of the atmosphere.
  • Weather occurs in this layer.

2.Stratosphere -

  • The second layer of Earth's atmosphere.
  • Contains Ozone layer.

3. Mesosphere -

  • The third layer above the stratosphere.
  • Coldest layer.

4. Thermosphere -

  • The fourth layer of the atmosphere.
  • Warmest layer.
  • Ionosphere - lowest level of thermosphere above mesosphere.
  • Aurora Borealis, Northern and Southern lights are seen in this layer.
  • Exosphere - outermost layer of thermosphere.
  • Satellites are in this layer.
  • Outer space with no gravity.

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A couple plans to have a child. the mother is homozygous for an autosomal recessive mutation. the father is heterozygous for the
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<u>Answer</u>:

  • The possible genotypes of the children are Hh and hh.
  • The probability of genotype Hh = 1/2
  • The probability of genotype hh = 1/2

<u>Explanation</u>:

  • <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
  • An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
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Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>

Note : An image is attached representing the cross in a Punnett square.

  • The probability of an event = No. of favourable outcomes/total no. of outcomes

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2



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