After 1.4 seconds, t = 1.4.
h(t) = 150 - 9(1.4)
Multiply 9 by 1.4 to get 12.6.
h(t) = 150 - 12.6
Subtract 12.6 from 150 to get 137.4.
h(t) = 137.4.
The height of the ball would be 137.4 after 1.4 seconds.
Hope this helps!
Answer:
1/8
Step-by-step explanation:
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Calculus</u>
Discontinuities
- Removable (Holes)
- Jump (Piece-wise functions)
- Infinite (Asymptotes)
Step-by-step explanation:
<u>Step 1: Define</u>
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<u>Step 2: Simplify</u>
- [Frac - Numerator] Factor quadratic:

- [Frac - Denominator] Factor GCF:

- [Frac] Divide/Simplify:

When we divide (x + 2), we would have a <em>removable</em> <em>discontinuity</em>. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.
Answer:
Negative, linear
Step-by-step explanation:
If you look at it, it is relatively in a line and the values are going down.
Answer:
10 square units
Step-by-step explanation:
We want to find the area under the curve
from x=1 to x=3.
We use definite integrals to find this area.

We integrate to obtain:

We evaluate the limits to get:


Therefore the area under the curve from x=1 to x=3 is 10 square unit.