The answer is B....................................................................................
well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.
![\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbf%20%7C2x-5%7C%3D4%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%282x-5%29%3D4%5Cimplies%202x%3D9%5Cimplies%20x%3D%5Ccfrac%7B9%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20-%282x-5%29%3D4%5Cimplies%202x-5%3D-4%5C%5C%5B1em%5D%202x%3D1%5Cimplies%20x%3D%5Ccfrac%7B1%7D%7B2%7D%20%5Cend%7Bcases%7D%20)
The length of the parking lot is 89m.
To find the length, we can abide by the following formula:
L = A/W
where L is the length, A is the area, and W is the width.
Given this formula, we can set up an equation:
7,031 / 79 = 89
The length of the parking lot is 89 meters.
Answer:
The average rate of change from x=0 to x=1 for f(x) is 0.
Step-by-step explanation:
We are given the function 
.
Now, the rate average rate of change of a function from 
to 
is given by 
.
As, we need the rate of change from x = 0 to x = 1.
So, we will find the values of f(0) and f(1).
i.e. 
i.e. f(0) = 3
and 
i.e. 
i.e. f(1) = 3
Thus, the rate of change from x=0 to x=1 is 
i.e. 
i.e. 0
Hence, the average rate of change from x=0 to x=1 for f(x) is 0.
Answer:
(1, -1)
Step-by-step explanation:
we isolate y in the first equation
2x+y=1
-2x. -2x
y=1-2x
and now we fill y into second equation
4x-2(1-2x)=6
4x-2+4x=6
8x-2=6
+2 +2
8x=8
/8 /8
x=1
and now to find y we insert x
2(1)+y=1
2+y=1
-2. -2
y= -1
hopes this helps
