Answer:
Null hypothesis: There is no significant difference in aging time of old methods of culturing cheese and the new method of culturing cheese.
Or
H0:μ1=μ2.
Alternative hypothesis: The new method of culturing cheese reduces aging time as compared to old method of culturing cheese
Or
Ha:μ1>μ2.
Step-by-step explanation:
We are interesting in investigating that whether the the new method of culturing cheese significantly reduces aging time compared to old method of culturing cheese. Null hypothesis always contain equality so, in null hypothesis we make the statement of no difference among both methods of culturing cheese. So, null hypothesis can be written as
Null hypothesis: There is no significant difference in mean aging time of old methods of culturing cheese and the new method of culturing cheese.
Or symbolically it can be written as
H0:μ1=μ2
whereas μ1 represents mean aging time for old method and μ2 represents mean aging time for new method.
Alternative hypothesis includes difference in methods which in this case is the claim about new method of culturing cheese reduces aging time. So, it means that mean aging time of old method will be greater than mean aging time of new method. So, the alternative hypothesis can be written as
Alternative hypothesis: The new method of culturing cheese reduces mean aging time as compared to old method of culturing cheese
Or symbolically it can be written as
Ha:μ1>μ2
whereas μ1 represents mean aging time for old method and μ2 represents mean aging time for new method.
2/5 of instruments= brass
1/3 of instruments= percussion
so add 2/5 and 1/3= 6/15+5/15= 11/15
So 15/15-11/15= 4/15
So Woodwinds make up 4/15 of the band
X + 25 < 75
hope it helps
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Answer:
1. y + 10 - 3/2y = -y/2 + 10
2. 2r+ 7r-r - 9 = 8r - 9
3. 7 + 4p-5+p+2q = 2 + 5p + 2q
Step-by-step explanation:
basically you can add terms that have the same variable
integers can be added together, Xs can be added, Zs, Ys, As, Bs, Cs, you get the point
1. y + 10 - 3/2y = -y/2 + 10
2. 2r+ 7r-r - 9 = 8r - 9
3. 7 + 4p-5+p+2q = 2 + 5p + 2q (do not add different variables p and q ) together
try 4-6 on your own to get this skill down, if you need help with those just let me know
She can wear outfits differently in 167 days.
Given that Lucy wants to wear different clothes everyday, and she has 8 dresses, 7 pairs of shoes, and 3 pairs of earrings, and Lucy can choose 1 dress, 1 pair of shoes, and 1 pair of earrings every day, but however 1 dress and 1 pair of shoes don't look good together, to determine, in such circumstances, how many days can she wear outfits differently, the following calculation must be made:
- (8 x 7 x 3) - 1 = X
- 168 - 1 = X
- 167 = X
Therefore, she can wear outfits differently in 167 days.
Learn more about maths in brainly.com/question/17002975
