Question

Please help!!!!

Answer 1

Step-by-step explanation:

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Answer 2

A)

the sum of all interior angles on any polygon is 180( n - 2 ), where is n = sides in the polygon.

now, this is a quadrilateral, so it has 4 sides, so the sum of all interior angles in degrees for it will be 180( 4 - 2), namely 360°, we know the angle at B is 90°, thus

$\bf \stackrel{B}{90}+\stackrel{A}{2x}+\stackrel{D}{3x}+\stackrel{C}{x}~~=~~360\implies 90+6x=360\implies 6x=270 \\\\\\ x = \cfrac{270}{6}\implies x = 45$

B)

well, if we dilate or blow up the quadrilateral, the angles always remain the same, same if we shrink it, now, points A and B are colinear, they're lying on the same line, we know B is 90°, hmmm what is A anyway? well, A is 2x, but we know x = 45, thus A is 2(45) = 90°.

since the angle at A is 90° and the angle at B is 90°, and both stem from the same colinear line, the lines AD and BC are perpendicular to AB and also parallel lines, no matter how you scale them, down or up.