Answer:
The area of APC is 70m². The area of triangle PMC is 35m².
Step-by-step explanation:
Let the area of triangle ABC be x.
It is given that AM is median, it means AM divides the area of triangle in two equal parts.
.....(1)
The point P is the midpoint of AB, therefore the area of APC and BPC are equal.
......(2)
The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.
.....(3)
The area of triangle APM is 35m².



Therefore the area of triangle ABC is 140m².
Using equation (2).



Therefore the area of triangle APC is 70m².
Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².



Therefore the area of triangle PMC is 35m².
Adjacent angles<span> are two </span>angles<span> that have a common vertex and a common side.
<OPN and <TSP have a common side but do not have a common vertex.
<OPN and <RSU do not have a common side or a common vertex.
<OPN and <QPN are adjacent angles. They have a common side and a common vertex.
<OPN and <QPS have common vertex but do not have a common side.</span>
9514 1404 393
Answer:
C log3(√((x -4)/x)
Step-by-step explanation:
The applicable rules of logarithms are ...
log(a/b) = log(a) -log(b)
log(a^n) = n·log(a)
The base is irrelevant, as long as all logs are to the same base.
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If you don’t mind me asking what is the question I’m confused because I might be able to help but I have no clue what the question is.