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Phoenix [80]
3 years ago
11

-QUICKLY ANSWER PLEASE- How do I factor expressions with variables?

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

There are many different types of expressions.

To factor expressions with variables, the first thing is to <u>take out any common factors always</u> across all terms.

                          Ex: 5x + 15

                              = 5(x + 3)

To factor trinomials with one variable (standard form): ax^{2} + bx + c = 0, after taking out the common factor if there is one, you can:

i) Use the quadratic formula. x = \frac{-b +- \sqrt{b^{2} -4ac} }{2a}

ii) Decomposition (factors of a and c multiply and added to give b)

Ex: 2x² - 7x + 3         2 * -3 = -6

(2                   -1 )         1 * -1 = -1

(1                   -3 )                      -6 + -1 = -7

=(2x-1)(x-3)

Trinomials with two variables like: ax² + bxy + cy² = 0

Use decomposition but include the second variable.

Ex: 2x² - 7xy + 3y²         2 * -3 = -6

(2                   -1 )         1 * -1 = -1

(1                   -3 )                      -6 + -1 = -7

=(2x-1y)(x-3y)

When a square value is being subtracted from another square value.

Difference of squares: x^{2} - y^{2} = (√x² - √y²)(√x² + √y²)

Ex: 36x² - k²

= (6x - k)(6x + k)

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Exercise 5.2. Suppose that X has moment generating function
soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) M_{X}(t)=E(e^{tX})

or

⇒ =\sum e^{tx}p(x)

⇒ =\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}

Step-by-step explanation:

Given:

moment generating function  of X as:

MX(t) = \frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}

a)  Now

Mean, E(X) = M_{X}'(t=0)

Thus,

M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}

or

M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}

also,

E(X^{2})=M_{X}''(t=0)

Thus,

M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}

or

M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}

Therefore,

Mean, E(X) = M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}

or

Mean, E(X) = - 0.5

and

E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}

or

E(X^{2}) = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

M_{X}(t)=E(e^{tX})

or

⇒ =\sum e^{tx}p(x)

⇒ =\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}

Therefore,

at x = 0, P(x) = \frac{1}{2}

at x= - 4 ,P(x) = \frac{1}{3}

at x = 5, P(x) = \frac{1}{6}

Thus,

E(X) =\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})

or

E(X) = - 0.5

also,E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})

E(X^{2})  = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0
4 years ago
What is the slope of the line passing through the points (-3, 4) and (2, -1)
dybincka [34]

Answer:

-1

Step-by-step explanation:

The answer is b, -1.

I do not have a step by step explanation for that.

4 0
3 years ago
Read 2 more answers
Hii please please help i’ll give brainliest if you give a correct answer tyyyyy
bezimeni [28]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

40%

Step-by-step explanation:

6 apples out of 15 fruits = \frac{6}{15}

\frac{6}{15} is equivalent to \frac{2}{5}

\frac{2}{5} is equivalent to 40%

<em>So your answer is 40%</em>

<em />

I hope this helps!

- sincerelynini

7 0
3 years ago
HEEEELP PLEAAASE I NEED THISSS!!!!!!!!!!!!!!! BRANILIEST FOR THR RIGHT ANSWER
Andru [333]

Answer:

2x

Step-by-step explanation:

I think so not sure try it tho

5 0
3 years ago
Greg has a bag of beads that contains 16 black, 20 red, and 4 white beads. He randomly picks a bead, places it back into the bag
Anton [14]
The answer is 9bt if you gave me the rest of the question I would maybe be able to get the real answer.
7 0
4 years ago
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