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3 years ago

I’m actually begging guys please help me

Mathematics

1 answer:

harina [27]3 years ago

7 0

Answer:

27.5

Step-by-step explanation:

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How to break down 1 1/3 into 4 equal parts

Serjik [45]

Answer:

1 1/3 in 4 equal parts: okay so.. 1/3 x 4 = 1 1/3 so therefore,

Step-by-step explanation:

to break it into 4 equal parts, you need to do as such (you can draw thic pic if u want) (i hope you can read this i have terrible handwriting)

4 0

3 years ago

The internal dimension of a cylindrical container has a base area of 20 cm^2 and a height of 10 cm. What is the internal volume

yawa3891 [41]

Answer:

C) 200 cm^3

Step-by-step explanation:

we observe that

Area=20 cm² and Height=10 cm

The formula to find volume is :

Volume= Area×Height

putting the values of area and height in above formula,we get

Volume= 20 cm²×10 cm

Volume= 200 cm³

The internal volume of the container is 200 cm³.

hope this helps

5 0

3 years ago

Plz help me with this!!!!

julia-pushkina [17]

Answer:

by the distance formula

the points are (2,2) and (-2,7)

and subtituting d=sqrt((2-(-2))^2+(2-7)^2)

which is equal to sqrt of 41

and it is equal to 6.40

3 0

3 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

3 years ago

1) How is circumference different than area?

Fiesta28 [93]

Answer:

0.8? maybe

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers