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Mazyrski [523]
2 years ago
11

I’m actually begging guys please help me

Mathematics
1 answer:
harina [27]2 years ago
7 0

Answer:

27.5

Step-by-step explanation:

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Solve the system of equations –2 + y = 14 and -5x – 7y=10 by combining the
pochemuha

Answer:

Step-by-step explanation:

-2+y=14

-5x-7y=10

y=14+2

y=16

-5x-7(16)=10

-5x-112=10

    +112  +112

-5x=122

x=-24.4

5 0
2 years ago
Mohamed and Li Jing were asked to find an explicit formula for the sequence -5, -25, -125, -625,....
Nuetrik [128]

Answer:

Li Jing's formula i.e.  \boxed{g_n=-5\cdot \:5^{n-1}}  is right.

Step-by-step explanation:

Considering the sequence

-5,\:-25,\:-125,\:-625,...

A geometric sequence has a constant ratio r and is defined by

g_n=g_0\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{g_{n+1}}{g_n}

\frac{-25}{-5}=5,\:\quad \frac{-125}{-25}=5,\:\quad \frac{-625}{-125}=5

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=5

So, the sequence is geometric.

as

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

g_1=-5

r=5

so

g_n=g_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

g_n=-5\cdot \:5^{n-1}

Therefore, Li Jing's formula i.e.  \boxed{g_n=-5\cdot \:5^{n-1}}  is right.

8 0
3 years ago
Pls help i will mark brainliest!:) thank you!;D
pashok25 [27]
<h2><em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em></h2>

<em><u>H</u></em><em><u>e</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>g</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>g</u></em><em><u>r</u></em><em><u>a</u></em><em><u>p</u></em><em><u>h</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>B</u></em>

<em><u>T</u></em><em><u>o</u></em><em><u> </u></em><em><u>f</u></em><em><u>i</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>:</u></em><em><u> </u></em><em><u> </u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>g</u></em><em><u>r</u></em><em><u>a</u></em><em><u>p</u></em><em><u>h</u></em><em><u> </u></em>

<em><u>=</u></em><em><u> </u></em>

<em><u>\sqrt{ {(x2 - x1)}^{2} }  +  \sqrt{ {(y2 - y1)}^{2} }</u></em>

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>P</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>)</u></em>

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>,</u></em><em><u>6</u></em><em><u>)</u></em>

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<em><u>\sqrt{ {(0 - 0)}^{2} }  +  \sqrt{ {(6 - 3)}^{2} }</u></em>

<em><u>\sqrt{ {3}^{2} }</u></em>

<em><u>3</u></em>

So 3.0 is the distance

Hope it helps

7 0
2 years ago
Solve the equation the square of 2x + 1 equals the square of x + 4
gavmur [86]
I am sorry this is where I can get too.

8 0
3 years ago
A jar has 20 marbles: 3 green, 12 blue, 5 red.
nadezda [96]

Probability is defined as the <u>likelihood or the certainty</u> that an event is going to<u> occur or happen.</u>

The probability of randomly choosing a red and then a green marble is 3/76.

The total number of marbles = 20

The number of green marbles= 3

The number of blue marbles = 12

The number of red marbles = 5

<u>The probability of choosing a red marble</u> = Number of red marbles / Total number of marbles

= 5/20

<u>In simplest fraction form</u> = \frac{1}{4}

We are told in the question that you keep the red marble you choose, So this means the <u>total number of marbles</u> left reduces to 19

<u>The probability of choosing a green marble is</u> =  Number of green marbles / New total number of marbles

= 3/19

Therefore, <u><em>the probability of randomly choosing a red and then a green marble is </em></u>

P (Red) x P(Green)

= 1/4  x 3/19

= 3/76

To learn more, visit the link below:

brainly.com/question/22563776

4 0
2 years ago
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