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3 years ago

11

I’m actually begging guys please help me

1 answer:

harina [27]3 years ago

7 0

Answer:

27.5

Step-by-step explanation:

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Lim x → 0 sin3x)/5x^3 -4

JulsSmile [24]

$\bf \lim\limits_{x\to 0}\ \cfrac{sin^3(x)}{5x^3}-4
\\ \quad \\\\ \cfrac{sin^3(x)}{5x^3}-4\implies \cfrac{[sin(x)]^3}{5x^3}-4
\\ \quad \\
 

\cfrac{[sin(x)]^3}{x^3}\cdot \cfrac{1}{5}-4
\\ \quad \\
thus
\\ \quad \\
\lim\limits_{x\to 0}\cfrac{[sin(x)]^3}{x^3}\cdot \lim\limits_{x\to 0}\cfrac{1}{5}-4\qquad \boxed{recall \qquad \lim\limits_{x\to 0} \cfrac{sin(x)}{x}\implies 1}
\\ \quad \\
1\cdot \cfrac{1}{5}-4$

8 0

3 years ago

Please help please n ty<3:)

VLD [36.1K]

Question 4 is 73 degrees. Question 5 is 60 degrees. Question 6 is 83 degrees. Question 7 is 50 degrees. Question 8 is 61 degrees. Hope this helps!(;

6 0

4 years ago

5-4+7x+1=_x+_ For No Solution, One solution, and Infinitely many solutions

gavmur [86]

7x+2 I'm not sure what solution it is though sorry

5 0

3 years ago

if a point P(x, y) which divides the line joining the points A(x1,y1) and B(x2,y2) in the ratio 1:1 then the coordinates of

Kobotan [32]

Answer:

This should help friend:

Step-by-step explanation:

Hope u r well

give me thanks, brainliest and 5 star plz

6 0

3 years ago

Can anyone please answer answer question 7.<br> Also it takes awhile to load the picture.

vredina [299]

It is 'c 'the answer

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3 years ago