<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- To convert the given equation into standard form.
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the standard form of the line is ,
ax + by + c = 0
So the given equation is ,
y = 2/5x -1/3
y = 6x - 5/15
15y = 6x - 5
6x -15y -5 = 0
<u>Hence</u><u> the</u><u> required</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>6</u><u>x</u><u> </u><u>-15y-5=</u><u>0</u><u>.</u>
L=2W-4
PERIMETER=2L+2W
58=2(2W-4)+2W
58=4W-8+2W
58=6W-8
6W=58+8
6W=66
W=66/6
W=11 ANS. FOR THE WIDTH.
L=2*11-4
L=22-4
L=18 ANS. FOR THE LENGTH.
PROOF:
58=2*18=2*11
58=36+22
58=58
Answer:
D is the correct answer i think
Step-by-step explanation:
Step-by-step explanation:
1. Ampltiude is 1
The period is

is the period
The phase shift is 0
2. The Ampltiude is 2
The period is 2 pi
The phase shift is 1
3. The amplitude is 3
The period is 2 pi/3
The phase shift is -2
4.The amplitude is 2/3
The period is -10pi
The phase shift is 0
5. The Ampltiude is 1
The period is -2 pi
The phase shift is pi
6. The amplitude is 1/4
The period is -4pi
The phase shift is negative 2pi/3
7. The Ampltiude is 3
The period is 4
The phase shift is 8