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3 years ago

If the numbers -2.5, -1.6, -3 1/10, - 1/10, and -0.5 were graphed on a number line, which would appear farthest to the left?

1 answer:

7 0

Turn the question around.
If all the numbers were positive: 2.5, 1.6, 3 1/10, 1/10, and 0.5, which would be farthest to the right?

The fact is that the negative numbers are a reflection of the positive numbers.
Since 3 1/10 would be farthest to the right with positive numbers, -3 1/10 will be farthest to the left with the negative numbers.

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LxWxH pls and thank u

lutik1710 [3]

l = 2in

b = h = 3in

now , Lbh

= 2×3×3

= 18 in³

i hope this helps

4 0

3 years ago

Area of a kite!!!!!!!!!!!!!!!

Ulleksa [173]

Find the area of each triangle then and them together, so:

1/2(15×8) =60

plus

1/2(15×8) =60

plus

1/2(23×8)=92

plus

1/2(23×8)=92

60+60+92+92=304

304 is the total area.

7 0

3 years ago

Read 2 more answers

If i have 900 gallons of gas. how much tank does do we need to fill up 20?

Gelneren [198K]

Answer:

the answer is 18000

Step-by-step explanation:

900 gallons multiply 20

so our answer is =18000

4 0

3 years ago

Read 2 more answers

Audrey has $120 to spend on a tennis racket and lessons the racket cost $45 and the lessons cost $15 per hour to find the variab

Leni [432]

Answer:

120 = 15x + 45 5 hours of lessons

Step-by-step explanation:

120 is total money so that goes on one side.

45 is a one-time cost so it is on its own.

15 per hour is another cost but this one depends on a variable so it has an x.

X represents the number of hours.

You put this together to from the equation: 120 = 15x + 45.

Subtract 45 from both sides: 75 = 15x

Divide 15 from both sides: 5 = x.

X = hours so 5 hours

7 0

2 years ago

Read 2 more answers

How do you solve 9| x+8 | + 10 < 55 & how is it graphed

mafiozo [28]

Hello!

First, let's write the problem.
$9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55$
Subtract 10 from both sides.
$9\left|x+8\right|+10-10\ \textless \ 55-10$
$9\left|x+8\right|\ \textless \ 45$
Divide both sides by 9.
$\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}$
$\left|x+8\right|\ \textless \ 5$
When we got absolute value, we are going to get two results.
$x+8\ \textless \ 5$
and
$x+8\ \textgreater \ -5$

Let's solve the first one,
$x+8\ \textless \ 5x+8\ \textless \ 5$
Subtract 8 from both sides.
$x+8-8\ \textless \ 5-8$
$x\ \textless \ -3x\ \textless \ -3$

Let's solve the second one.
$x+8\ \textgreater \ -5$
Subtract 8 from both sides.
$x+8-8\ \textgreater \ -5-8$
$x\ \textgreater \ -13x\ \textgreater \ -13$

Let's combine the ranges.
$-13\ \textless \ x\ \textless \ -3$

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

3 0

3 years ago