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Pepsi [2]
3 years ago
14

a container holds 15 pennies 8 nickels and 10 dimes you will randomly select two coins without replacement what is the probabili

ty you will select a dime on your second draw if you do not select a dime on your first draw
Mathematics
1 answer:
nalin [4]3 years ago
5 0
SOLUTION: A container holds 15 pennies, 8 nickels, and 10 dimes. You will randomly select two coins without replacement. -->Fill in the probabilities on a tree diagram.
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24

Step-by-step explanation:

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Step-by-step explanation:

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Create a word problem that the equation 4x + 32 = 164 could represent.
Svetlanka [38]

It is a hot summer day, and Jade is trying to save money to buy a new shoe. She has 32 dollars, and she plans to sell smoothies at her neighborhood for four dollars a cup. At the end of the day, she is left with a total of 164 dollars in her wallet. How many smoothies did Jade sell?

3 0
2 years ago
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PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
Liula [17]

Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

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4 years ago
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Use the following regression results to answer the remaining questions. Y measures average hourly earnings AHE in U.S. dollars f
Ulleksa [173]

Answer:

Check the explanation

Step-by-step explanation:

Y = 11.5 + 4.5*X1 -2.5*X2 +0.7*X3+1.6*X4 -2.4*X5 -2.8*X6

FOR JANE

X1 =1 , X2 =1 , X3 =5 , X4 =0 ,X5=0, X6=1

SO,

Y =11.5+(4.5*1)-(2.5*1)+(0.7*5)+0+0-(2.8*1)

= 14.2

..........................

FOR Sophie

X1 =1 , X2 =1 , X3 =10 , X4 =1 ,X5=0, X6=0

so,

Y =11.5+(4.5*1)-(2.5*1)+(0.7*10)+ (1.6*1)+0+0

= 22.1

3 0
4 years ago
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