Factor the following polynomial completely. Start by getting the GCF of the polynomial. 2x^3-18x

I have to study for a test. It's for data management. Does anyone have tips? (Grade 7)

Vinil7 [7]

Studying: Use resources.

If your studying for a test, use some resources, like quizizz, quizlet, flashcards, or the internet. If you do, ask your parents for help. Think it like its your big test, and your studying a lot. If you study and try, you'll pass the test on data management. If you need it, ask your teacher for tutoring or practice some data management questions. Studying will help you not to fail a test.

Now, we'll talk about before the test.

Before test: Rest, eat breakfast, and stay calm.

Step-by-step explanation: Going to bed before a test can prevent you from going to sleep. For example, GMAS (for me) is coming soon, and my teacher encourage us to rest, eat breakfast and stay calm. A recommended time for you to go to bed is 8:00-9:30.

Now, about breakfast.

Eating breakfast is also important because you can perform better, in fact, scientists say that if students eat breakfast before a test or exam, they will perform better! Whatever you do, don't skip breakfast. If you do, you won't perform good, and theirs a chance you could fail.

Now, staying calm is the big one.

If your freaking out, stay calm, say a prayer and get your work done! Staying calm is the big one because most students (I am one of them) get worried if they're gonna fail. Keep this in mind: <u>Try. Your. Best.</u> If you don't try, you won't achieve anything. And please don't cheat. If you cheat, you'll have to repeat the whole grade. Can't cheat in college; you'll get kicked out.

During test: DO. NOT. CHEAT.

CHEATING WILL GET YOU KICKED OUT OF COLLEGE AND YOU'LL AUTOMATICALLY FAIL!!! If your computer prevents you from going to other sites, that is good, but don't pull out ANY study guides or notes during your test, unless it's open-notes. If you don't know a questions, skip it and go to the next one. Then go back, it will come to mind later. If your done with your test early, check your answers. Look back and think, "Is this correct?"

Hope you do good on your test!

~ Lily, from Brainly.

3 0

3 years ago

• karger's min cut algorithm in the class has probability at least 2/n2 of returning a min-cut. how many times do you have to re

MrRissso [65]

The Karger's algorithm relates to graph theory where G=(V,E) is an undirected graph with |E| edges and |V| vertices. The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs. The algorithm is randomized and will, in some cases, give the minimum number of cuts. The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2), which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n

We will use a tool derived from calculus that
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e for x finite.

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n)
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n) [note: log(n) is natural log]

4 0

3 years ago

im almost done with this hw. plz help!!! give explanation if you actually know the answer so ik u dont just want points

s344n2d4d5 [400]

Answer:

B

Step-by-step explanation:

6 0

2 years ago

Which expression would be easier to simplify if you used the associative property to change the grouping? O A. (170 + 30) – 41 O

jekas [21]

Answer:

A.(170+30)-41

Step-by-step explanation:

(170+30)-41=170+(30-41)

200-41=170+(-11)

159=170-11

159=159

3 0

2 years ago

4x + 1/3 y 2 what is the value of the expression above when x = 2 and y = 3

GenaCL600 [577]

Hoi!

To solve this, first plug in the values for x and y.

x = 2, so anywhere you see x, put 2 in its place.

y = 3, so anywhere you see y, put 3 in its place.

$4(2) + \frac{1}{2}(3)$

4 × 2 = 8

$\frac{1}{2}$ × 3 = $1 \frac{1}{2}$

$8 +1 \frac{1}{2}$ = $9 \frac{1}{2}$

$9 \frac{1}{2}$ is your answer.

4 0

2 years ago

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