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PilotLPTM [1.2K]
3 years ago
14

Last week you worked 20 hours, and earned $255.

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

Answer:$12.75

Answer:$12.75Step-by-step explanation:

The hourly pay rate is $12.75 because all you have to do is divide $255 from 20 and you get $12.75

You might be interested in
a ruby throated hummingbird is about 4 in long and is it noted for its annual non-stop migration of 500 miles across the Gulf of
Goshia [24]

Answer:

7,920,000

Step-by-step explanation:

The question is asking the number of times that 4 inches fits in 500 miles. We need to divide 500 miles by 4 inches, but first we need to convert 500 miles into inches.

12 inches = 1 foot

5280 ft = 1 mile

500 miles * (5280 ft)/(1 mile) * (12 in.)/(1 ft) = 31,680,000 inches

Now that we know that 500 miles is the same as 31,680,000 inches, we divide that number of inches by 4 inches.

(31,680,000 inches)/(4 inches) = 7,920,000

Answer: 7,920,000

5 0
3 years ago
Bill went on a very long run, so he ran kind of slowly. He ran 2 miles in 30 minutes. How many miles would he run in three hours
FromTheMoon [43]

Answer:

12 miles

Step-by-step explanation:

There are 3 hours = 180 minutes

180÷30=6

6×2=12

Hope that helps!

7 0
3 years ago
MAKE IT 100% CORRECT
ahrayia [7]
I think <1 & <2 are vertical
<3 & <4 are adjacent
7 0
3 years ago
A bike costs $200 but is reduced by 35% how much does the bike cost now?
iVinArrow [24]

Answer:

The bike costs $130.

Step-by-step explanation:

1) 200 x 0.35 = 70

2) 200 - 70 = 130

4 0
3 years ago
Read 2 more answers
Five years back, Michael's age was 2/3 the age of James. After ten years he will be 5/6 of the age of James. What are the equati
irakobra [83]
I find it easier to start from scratch and write out the equations, then compare them with the given equations.

Let m and j represent the ages of the two boys.  Then m-5=(2/3)(j-5)
Also, in ten years:  m+10 = (5/6)j.

Let's solve this system:  Mult the first eqn by 3 to remove the fraction:
3(m-5) = 2(j-5), or 3m - 15 = 2j -10.  Next, mult. the 2nd eqn by 6 to remove the fraction:  6m+60 = 5j.

Our two equations are (at this point)      3 m - 15 = 2j - 10 and
                                                                6m  +60  = 5j

Let's mult. the first equation by -2, so as to obtain the coefficient -6 for m:

-6m + 30 = -4j + 10
 6m + 60  = 5j
---------------------------
90 = j + 10, so j = 80 (wow!)

Let's now find m:  6m + 60 = 5(80), or    6m = 400+60 = 460

Then m = 76 2/3.

We must check our solution (m = 76 2/3, j = 80):

Let's subst. these values into     m-5=(2/3)(j-5)

Does 76 2/3 - 5 = (2/3)(80) - 10/3?

Does 76 2/3 - 15/3 = 160/3 - 10/3?

Does 76 - 15 = 160 - 10    No.  So something's wrong here.

Going back to the problem statement:

<span>x-5=2/3(y-5) and x+10=5/6(y+10)  seems correct!


Mike's age 5 years ago was x-5, and james' age 5 years ago was y-5.  The multiplier (2/3) is also correct.

Mikes age 10 years from now will be x+10, and james' y+10.

The first answer set is the correct one.</span>
7 0
3 years ago
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