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Liula [17]
2 years ago
8

Work out the area of this quarter circle of radius 8cm, Give you answer in terms of pi

Mathematics
1 answer:
oee [108]2 years ago
3 0

Answer:

The area of the quarter circle is 16\pi\ cm^{2}

Step-by-step explanation:

we know that

The area of a quarter circle is equal to

A=\frac{1}{4}\pi r^{2}

we have

r=8\ cm

substitute the value

A=\frac{1}{4}\pi (8)^{2}

A=16\pi\ cm^{2}

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The sale price of an item on sale for 40% off is $48. What was the regular price?
Charra [1.4K]

Good evening ,

<u><em>Answer:</em></u>

<h2>the regular price of the item is $80.</h2>

<u><em>Step-by-step explanation:</em></u>

Let p represent the regular price of the item.

p - p×(40/100) = 48 ⇌ p×(1 - 40/100) = 48 ⇌ p×(100/100 - 40/100) = 48

⇌ p×(60/100) = 48 ⇌ p = (480×100)/60 = 48 000/60 = 80.

____________________________________________

:)

5 0
3 years ago
Read 2 more answers
The equation of the line of best fit of a scatter plot is y = _7x _ 2. What is the the y-intercept?
DaniilM [7]
The solution to your problem is as follows:

Since the equation of a line is:

y = mx + b; where m=slope, and b=y-intercept.

Therefore, the y-intercept of the line is -2.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Parallelogram<br> b=12 cm, h=10 cm, a=
Anna35 [415]
Answer: 120 cm^2

Step-by-Step Explanation:

Base (b) = 12 cm
Height (h) = 10 cm
Area (a) = bh

Therefore,
= bh
= b * h
= 12 * 10
=> 120

Area (a) = 120 cm^2
5 0
1 year ago
How tall is the flagpole?
Fudgin [204]
51 ft is the answer

Explanation

The hight of the man divided by the hight of school ( which is unknown )

Equal

The length of the shadow of the man divided by the shadow of the school

Cross multiplication and find the value of unknown x which is 51... and ya
4 0
2 years ago
Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!
Rudiy27

Use these equations when converting polar equations to parametric equations:

x=r\cos\theta

y=r\sin\theta

We know that r=5\theta, so substitute that into both equations for x and y.

x=5\theta\cos\theta

y=5\theta\sin\theta

Now, replace \theta with any variable that you want to represent the parametric equations in. I'll use the standard variable, t

x=5t\cos t

y=5t\sin t

Thus, r=5\theta represented in parametric form is:

(x,y)=(5t\cos t, 5t \sin t)

Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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