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Yuliya22 [10]
3 years ago
5

Help! :) please!!! Thanks

Mathematics
1 answer:
Leto [7]3 years ago
7 0
I would use clustering to organize information when comparing and contrasting information. It allows you to explore the relationship between ideas.

Hope this helps
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A relationship that has a constant rate of change represented by a line.
MaRussiya [10]
The answer is rate of change
7 0
3 years ago
I need help 3-6 pleasr
Colt1911 [192]
3) Mathematical expression would be:
 412 - 65 + 0.50x
Where, x = Number of Texts sent

4) Product means result after multiplication, sum after addition, quotient is the result of division with remainder, and difference is how far two numbers are in their magnitude.
"Per" tells us the magnitude for an Unit value.

5) Associative property = (a+b) + c = a+ (b+c)
Commutative property = a + b = b + a
Distributive Property = a(b+c) = ab+bc

They all have their unique characteristics and can be differentiated on that basis.

6) They all are same.
At the end, without parentheses and in proper symbol, it would be equal to -3/4

Hope this helps!
4 0
4 years ago
Help ASAP<br><br><br> 22.41 + 8.9
Diano4ka-milaya [45]

Answer:

<em>22.41 + 8.9</em><em>=</em><em> </em><em>31.31</em>

<em>hope this helps</em><em> </em><em><</em><em>3</em>

8 0
3 years ago
Order of operations could someone please help me with this question? because i don't know how to completely work it out
malfutka [58]

Answer:

-15

Step-by-step explanation:

so to start you must distribute negative two times negative two equals positive four,

so now your equation looks like this,

2^2 +4+4-3^3

then you need to do the exponents,

2 x 2 = 4

3 x 3 x 3 =27

now it looks like this

4+4+4-27

12 - 27

-15

Hope that helps!

8 0
3 years ago
Super urgent!<br><br> Solve the equation for all real values of x. 3tan^2 = sqrt3 tanx
lutik1710 [3]

f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0

tan2(x) + √3[tan(x)] - tan(x) - √3 = 0

Factor into

[-1 + tan(x)]*[√3 + tan(x)] = 0

which means

[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0

Then

tan(x) = 1

tan-1(1) = pi/4 radians

For the other equation

[√3 + tan(x)] = 0

tan(x) = -√3

tan-1(-√3) = -pi/3

so that

x = pi/4 or -pi/3 in the interval [0, 2pi]

5 0
3 years ago
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