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2 years ago

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Four times a number is at least 2

1 answer:

IrinaK [193]2 years ago

4 0

Four times a number (4 times x since x represents unknown) is at least (<) two (2)

4x>2
divide both sides by 2
2x>1

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Part A: He can use distance formula. The formula is: $d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

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$\large\underline{\sf{Solution-}}$

$\textsf{Given expression;}\\$

$\rm{23 = \frac{7}{9}(6x - 36) + 9 } \\$

$\rm{\longmapsto} \: 23 = \frac{(42x - 256)}{9} + 9 \\$

$\rm{\longmapsto} \: 23 = \frac{(42x - 256 + 81)}{9} \\$

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<u>Simplfy in Algebra </u>

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$\displaystyle E=\sqrt{\frac{25x^9y^3}{64x^6y^{11}}}$

Simplifying like factors in the denominator and numerator

$\displaystyle E=\sqrt{\frac{25x^3}{64y^{8}}}$

All the factors are perfect squares except $x^3$ , thus we rewrite:

$\displaystyle E=\sqrt{\frac{25xx^2}{64y^{8}}}$

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