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oksian1 [2.3K]
3 years ago
13

What goes 2 what

Biology
1 answer:
sattari [20]3 years ago
4 0

The correct matches include the following list-

  • measure of an object's ability to transmit electricity- <u>Resistance</u>
  • potential energy per unit charge- <u>Voltage</u>
  • electric current that reverses direction in a circuit at regular intervals- <u>Alternating current </u>
  • electric current flowing in one direction only- <u>Direct current </u>

Explanation:

(A).  Resistance refers to the obstruction provided to the flow/ transmission of electric charge. Higher the resistance lower would be the transmission of electricity. It is calculated in terms of Ohm.

(B).  Voltage is potential energy generated per charge unit in terms of classical electrostatic physics. In terms of layman language is work done in moving a unit charge from one-point A to the corresponding other point B against the electric field.

(C).  Alternating current means a constantly alternating current which flows in a sinusoidal manner. By alternating nature, it means it reverses its polarity per unit time. They are the prime component of electricity supply to our homes from electricity distribution companies.

(D).  Direct currents are just reverse of Alternating current. By this, we mean that it flows in a fixed direction. They are produced from dry cells commonly.

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A model for a​ company's revenue from selling a software package is ​R(p)equals=−2.52^2400​p, where p is the price in dollars of
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A model for a​ company's revenue from selling a software package is ​R(p)=-2.5p² + 400​p, where p is the price in dollars of the software. What price will maximize​ revenue? Find the maximum revenue.

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Step-by-step explanation:

The maximum is the y-value of the Vertex.

Step 1: Use the Axis-Of-Symmetry (AOS) formula to find x:

x=\frac{-b}{2a}

R(p) = -2.5p² + 400

     a= -2.5  b=400

p=\frac{-(400)}{2(-2.5)}

         = \frac{-400}{-5}

        =80

∴ In order to maximize the value, the company will sell the software package for $80

Step 2: Find the maximum by plugging the p-value (above) into the given equation.

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