The calculator returns an error as the answer for the inverse sine of 1.055 because the acceptable range for sine is only from 0 to 1.00 in which 1.055 is clearly greater than. This is also the same as for the cosine values.
Answer:
The amount in the account in the beginning of the 6th year is $6375 .
Step-by-step explanation:
Formula
As given
You invest $5000 in an account at 5.5% per year simple interest.
Principle = $ 5000
Rate = 5.5 %
Time = 5 years
(As calculate amount in the account for beginning of 6th year.)
Putting all the values in the formula
Simple interest = $ 1375
Amount = Principle + Simple interest
Putting values in the above formula
Amount = $5000 + $1375
Amount = $ 6375
Therefore the amount in the account in the beginning of the 6th year is $ 6375 .
Lets put these numbers in order
1,2,3,3,4,5,6,7,8,8,9
Q1 = 3
Q2 (median) = 5
Q3 = 8
the box starts at Q1 and ends at Q3....so left side is 3 and right side is 8
u r correct...it is A
Answer:
yes wait im doing it. do I put them un order
Step 1
Anything divided by one gives itself.
\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−8 and
1
−8
=
48
−12
Step 2
Convert -8−8 to fraction -\frac{64}{8}−
8
64
.
\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−
8
64
and
1
−8
=
48
−12
Step 3
Compare \frac{1}{8}
8
1
and -\frac{64}{8}−
8
64
.
\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and
1
−8
=
48
−12
Step 4
Anything divided by one gives itself.
\text{false}\text{ and }-8=\frac{-12}{48}false and −8=
48
−12
Step 5
Reduce the fraction \frac{-12}{48}
48
−12
to lowest terms by extracting and canceling out 1212.
\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−
4
1
Step 6
Convert -8−8 to fraction -\frac{32}{4}−
4
32
.
\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −
4
32
=−
4
1
Step 7
Compare -\frac{32}{4}−
4
32
and -\frac{1}{4}−
4
1
.
\text{false}\text{ and }\text{false}false and false
Step 8
The conjunction of \text{false}false and \text{false}false is \text{false}false.
\text{false}false
Hint
Do the arithmetic.
Solution
\text{false}false
