F(q)=0
so, q^2 - 125 = 0
(q)^2 - (5)^2 = 0
(q+5) (q-5) = 0
q = 5, -5
1 is wrong there are two numbers greater than 4 but less than or equal to 6.
the first one was correct
The answer is a vertex. Corners of any shape are vertexes
You can not "solve" this, so to speak, rather simplify this expression. Take the "2" and multiply that by the "a" and the "3" in the parentheses. You will then have the simplified answer of: 2a times 6.
Hope that helps!
