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2 years ago

The largest prime number that is a factor of 35 is multiplied by the smallest prime number

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

6 0

Answer:

the largest factor of 35 is 35 and the smallest prime number is 2 so 35 times two is 70

Step-by-step explanation:

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Is it prime or polynomial

bogdanovich [222]

The expression: 4x² + 38x + 70 ; is a polynomial expression.
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7 0

3 years ago

2x-5/5 +x-2=3(x+5). Find the value of x?

deff fn [24]

Answer:

Step-by-step explanation:

$\frac{2x - 5}{5} + x - 2 = 3(x + 5)$

$\frac{2x - 5}{5} + x - 2 = 3x + 15$

$\frac{2x - 5}{5} = 2x + 17$

$2x - 5 = 10x + 85$

$-8x = 90$

$x = \frac{-45}{4}$

5 0

3 years ago

Pleaseee help me asap

valkas [14]

Answer:

(0,-3)

Step-by-step explanation:

You can just graph it and find the center.

Please put me as brainliest. Thank you.

7 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Which of the following rational numbers is equivalent to a terminating decimal?

anygoal [31]

A is the correct answer. When put into calculator, the decimals ends.

7 0

3 years ago