Answer:
Growth of $10,000 at 2% Interest
Year Amount
0 $10,000
1 $10,200
2 $10,404
3 $10,612
4 $10,824
5 $11,041
6 $11,262
7 $11,487
8 $11,717
9 $11,951
10 $12,190
$10,000 for 10 Years by Interest Rate
Rate Amount
1% $11,046
2% $12,190
3% $13,439
4% $14,802
5% $16,289
6% $17,908
8% $21,589
10% $25,937
12% $31,058
15% $40,456
20% $61,917
Step-by-step explanation:
Answer:
The number of cars passing or the people arriving during lunch hour will be around 220
Step-by-step explanation:
First we find the for ten minutes period from given data:
Average Cars in 10 minutes = (18+38+87+16+56+5)/6
Average Cars minutes = 36.67
Now, for average cars in 1 hr, we must multiply this value by 6. As, 10 minutes multiplied by 6 equals 1 hr.
Average cars in an hour = 36.67*6
<u>Average Cars in an hour = 220</u>
Hence, the number of cars or people arriving during lunch hour will also be equal to average number of cars arriving during an hour.
7x + 15x + 27 = 247
22x = 247 -27
22x =225
X= 10.22
Answer:
<em>The area of the shaded part = 61.46</em>
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Step-by-step explanation:
Assume the hypotenuse of the triangle is c (c>0)
As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.
The hypotenuse of the triangle can be calculated by Pythagoras theorem as following: 
=> c = 10
So that the semi circle has the diameter = 10 => its radius = 5
- The total area of 2 semi circles is equal to the area of the circle with radius =5
=> The total area of 2 semi circles is: 
x 
= 25
- The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x
x 
= 20
=> The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40
- The area of the square is:
= 
It can be seen that:
<em>The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles </em>
<em>= 100 - 25</em><em> + 40 = 61.46</em>
Answer:
v = (1/48)π
Step-by-step explanation:
v = (4/3)πr³
v = (4/3)π(1/4)³
v = (4/3)(1/64)π
v = (1/3)(1/16)π
v = (1/48)π
