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Law Incorporation [45]

2 years ago

15

The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the

Equation Editor. If such a symbol is needed, type "RightArrow." For example: P(0, 0) RightArrow P′(1, 2).
Write a translation rule that maps point
D
(
7
,

−
3
)
onto point
D
'
(
2
,

5
)
.

1 answer:

Naily [24]2 years ago

4 0

Dmdkdjkdjddjjfjjtjjtjfhfjtjt

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What is slope of the equation? 7x -2y = -10

irga5000 [103]

Answer:

m = 7/2

Step-by-step explanation:

Brainliest Please!!?!!!!

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Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

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There is no extraneous solution.

3 0

1 year ago

Pedro has 3 boxes of 6 markers. Rafael has 5 boxes of 5 markers. One of the friends arranges all his markers into 2 equal groups

Komok [63]

Answer:

see below

Step-by-step explanation:

Pedro has 3 boxes of 6 markers.

3*6 = 18 markers

We can divide this by 2 because this is even

18/2 = 9

There are 9 in each group

Rafael has 5 boxes of 5 markers

5*5 = 25

We cannot divide this by 2 because this is odd

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2 years ago

Please help me with this!!

Naddik [55]

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the $x$ values in the table. In other words, we need to replace $x$ with each value in our given function and simplify.

- For x = 0

$f(x)=(x-2)^2-5$

$f(0)=(0-2)^2-5$

$f(0)=(-2)^2-5$

$f(0)=4-5$

$f(x)=-1$

Since $x=0$ and $y=-1$ , our first point is (0, -1)

- For x = 1

$f(x)=(x-2)^2-5$

$f(1)=(1-2)^2-5$

$f(1)=(-1)^2-5$

$f(1)=1-5$

$f(x)=-4$

Our second point is (1, -4)

- For x = 2

$f(x)=(x-2)^2-5$

$f(2)=(2-2)^2-5$

$f(2)=(0)^2-5$

$f(x)=-5$

Our third point is (2, -5)

- For x = 3

$f(x)=(x-2)^2-5$

$f(3)=(3-2)^2-5$

$f(3)=(1)^2-5$

$f(3)=1-5$

$f(x)=-4$

Our fourth point is (3, -4)

- For x = 4

$f(x)=(x-2)^2-5$

$f(4)=(4-2)^2-5$

$f(4)=(2)^2-5$

$f(4)=4-5$

$f(x)=-1$

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

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2 years ago

A) make U subject of the formula E= m/2g(v^2-u^2)

ollegr [7]

Answer:

u = v2−2Egm−−−−−−−√

Step-by-step explanation:

2Eg = 2g (M2g(V2−U2)

2Eg = m(V2 - U2)

2Eg - mV2 - mU2

mU2 = mV2 - 2Eg

mU2m=mV2−2Egm

U2 = mV2−2Egm

= mV2m−2Egm

U2 = V2 - 2Egm

U = V2−2Egm−−−−−−−−√

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2 years ago