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GaryK [48]
3 years ago
12

Please help me please

Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

A for the second part

2/1

Step-by-step explanation:

an inequality is a comparison.

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NEED HELP ASAP please
svetlana [45]

Answer:

D.

Step-by-step explanation:

The problem is asking to multiply x-5 by x^2, so we can set it up to distribute the x^2 to both values. The final answer would therefore be x^2(x-5), which is D.

5 0
3 years ago
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Someone please help!!!!!!!!!
tino4ka555 [31]

Answer:

-32

Step-by-step explanation:

Simply input the x and y values.

New equation:

| 147-(-9) | /(-4) +7

Step one:

<em>147-(-9)   = 156</em>

<em>Step two:</em>

|156|/-4    =-39

Step three:

-39+7      =-32

If you evaluate the expression it comes out to -32

6 0
2 years ago
The time period, T, of a simple pendulum is directly proportional to the square root of the length, d, of the pendulum.
amid [387]

Step-by-step explanation:

T = k * sqrt(d), where k is a real constant.

When d = 6, T = 5.

k = T / sqrt(d) = 5 / sqrt6.

Therefore when d = 3, T = (5 / sqrt6) * sqrt3 = 3.53.

7 0
2 years ago
I need help with math -4+a=15
MrMuchimi

Note the equal sign. What you do to one side, you do to the other. Isolate the a.

Add 4 to both sides

a- 4 (+4) = 15 (+4)

a = 15 + 4

a = 19

19 is your answer for a

hope this helps

5 0
3 years ago
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Solve the following equation on the interval [0, 2π). tan^2x sin x = tan^2x
Alenkasestr [34]
<h3>Given</h3>

tan(x)²·sin(x) = tan(x)²

<h3>Find</h3>

x on the interval [0, 2π)

<h3>Solution</h3>

Subtract the right side and factor. Then make use of the zero-product rule.

... tan(x)²·sin(x) -tan(x)² = 0

... tan(x)²·(sin(x) -1) = 0

This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:

... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)

Then our equation becomes

... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0

... -sin(x)²/(1 +sin(x)) = 0

Now, we know the only solutions are found where sin(x) = 0, at ...

... x ∈ {0, π}

8 0
3 years ago
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