Answer:
D.
Step-by-step explanation:
The problem is asking to multiply x-5 by x^2, so we can set it up to distribute the x^2 to both values. The final answer would therefore be x^2(x-5), which is D.
Answer:
-32
Step-by-step explanation:
Simply input the x and y values.
New equation:
| 147-(-9) | /(-4) +7
Step one:
<em>147-(-9) = 156</em>
<em>Step two:</em>
|156|/-4 =-39
Step three:
-39+7 =-32
If you evaluate the expression it comes out to -32
Step-by-step explanation:
T = k * sqrt(d), where k is a real constant.
When d = 6, T = 5.
k = T / sqrt(d) = 5 / sqrt6.
Therefore when d = 3, T = (5 / sqrt6) * sqrt3 = 3.53.
Note the equal sign. What you do to one side, you do to the other. Isolate the a.
Add 4 to both sides
a- 4 (+4) = 15 (+4)
a = 15 + 4
a = 19
19 is your answer for a
hope this helps
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}