Using integration, it is found that the area under the graph of f(x) in the desired interval is of 1 unit squared.
<h3>How is the area under a graph found?</h3>
The area under the graph of a curve f(x) between x = a and x = b is given by the following integral:

In this problem, the function and the limits of integration are given by:


Hence:

Using substitution:



Hence:

Applying the Fundamental Theorem of Calculus:

Hence, the area under the graph of f(x) in the desired interval is of 1 unit squared.
To learn more about integration, you can take a look at brainly.com/question/20733870
Your answer is going to be c three.............
Hello. In <span>x3 − 11x2 + 24x = 0 please use the symbol " ^ " to denote exponentiation:
</span><span>x^3 − 11x^2 + 24x = 0
First step: factor out x:
</span>
x^3 − 11x^2 + 24x = 0 = x(x^2 - 11x + 24) = 0
Second step: factor the polynomial x^2 - 11x + 24 = 0.
We can see right away that (-3)(-8) = + 24 and that
-3
-8
---
is equal to -11. Thus, the factors of
x^3 − 11x^2 + 24x = 0
are x(x-3)(x-8) = 0. The solutions are 0, 3 and 8.
Yes, 5/12 is greater than 1/4.