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kaheart [24]
4 years ago
13

WILL GIVE BRAINLIEST TO CORRECT ANSWER!

Mathematics
1 answer:
krek1111 [17]4 years ago
3 0

Kevin ran 17 and steve ran 14 add them to gether and you get the sum of 31.

s+3=k


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Two forces of 401 newtons and 477 newtons act on a point. The resultant force is 828 newtons. Find the
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Answer:

The answer is "39.01^{\circ}"

Step-by-step explanation:

\to R= 828\\\\\to F_1= 401\\\\\to F_2=477\\\\\to \bold{R=\sqrt{F_1^2+F_2^2+2F_1F_2 \cos \theta}}

828=\sqrt{401^2+477^2+2 \times 401 \times 477 \cos \theta}\\\\828=\sqrt{160801+227529+382554 \cos \theta}\\\\828=\sqrt{388330+382554 \cos \theta}\\\\

square the above equation:

(828)^2=(\sqrt{388330+382554 \cos \theta})^2\\\\

685584 =388330+382554 \cos \theta\\\\685584 -388330=382554 \cos \theta\\\\297254=382554 \cos \theta\\\\\cos \theta=\frac{297254}{382554}\\\\\cos \theta=0.777025\\\\\theta= \cos^{-1} 0.777025\\\\\theta= 39.01^{\circ}

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