(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) =
(2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
Answer:
y +8 = -4(x -8)
Step-by-step explanation:
You recognize that the given equation is in slope-intercept form:
y = mx + b
with m = 1/4 and b = 5.
A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...
-1/m = -1/(1/4) = -4
The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . for slope m through point (h, k)
Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...
y +8 = -4(x -8)
Answer:
m
Step-by-step explanation:
m
An ordered pair is written like this, ( x, y ). In this case x = 0 and y = -3. On a graph the vertical line is the y-axis and the horizontal line is the x-axis. The origin is point ( 0, 0 ). To the left of the origin on the x-axis is the negative number line and to the right is the positive number line. On the y-axis, south of the origin is the negative number line and north is the positive number line. When you plot a point on a graph you do x first, so if x equals 1, you would move one right, -1, one left. IF y were to equal 2 then from the place where you are on the x-axis, 1, you would move two up, -2, two down. In this case x = 0 so you would stay at the origin, and y = -3 so you would move 3 down. So ( 0, -3 ) would lie negative y-axis. The answer is D.
