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3 years ago

9

Read the picture that's were the question is.

1 answer:

vlabodo [156]3 years ago

4 0

Answer:

X is your answer bc when coordinates are flipped over the x-axis the y coordinate goes negative

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The sum of two trinomials is 6x2 − 5x + 4. If one of the trinomials is 4x2 + 3x − 2, then what is the other trinomial?

Vadim26 [7]

Subtract the known trinomial from the total sum:

6x2 - 5x + 4 - 4x2 + 3x - 2 = 2X^2 -8x +6
I hope this helps :)

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2 years ago

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frosja888 [35]

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3 years ago

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zalisa [80]

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AleksAgata [21]

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3 years ago

Does anyone know the the answer to the second algebra question? Will give brainiest

astraxan [27]

Answer:

$\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}$

$\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}$

$x^{3} x^{\frac{1}{3} }$

Convert them, so they have a common denominator - $\frac{1}{3}$

$\frac{3}{1} * \frac{1}{3}= \frac{9}{3}$

$\frac{9}{3} + \frac{1}{3} = \frac{10}{3}$

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]

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3 years ago