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3 years ago

Read the picture that's were the question is.

Mathematics

1 answer:

vlabodo [156]3 years ago

4 0

Answer:

X is your answer bc when coordinates are flipped over the x-axis the y coordinate goes negative

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Which function is shown in the graph below?

dedylja [7]

Answer:

B is the answer

the graph is shifted up +3

the graph is curving upward, so the power has to be positive

6 0

3 years ago

3\sqrt{2} - 2\sqrt{18} + 6\sqrt{8}[/tex]

Stella [2.4K]

Answer:

$\sf \bold 9\sqrt{2}$

Step-by-step explanation:

<h3>Simplifying radicals</h3>

Step1: Prime fatorize and reduce to simplest form

Step2: Combine like radicals

$\sf 3\sqrt{2} - 2\sqrt{18}+6\sqrt{8}= 3\sqrt{2}- 2\sqrt{3*3*2}+6\sqrt{2*2*2}$

$\sf = 3\sqrt{2}-2*3\sqrt{2} +6*2\sqrt{2}\\\\=3\sqrt{2}-6\sqrt{2}+12\sqrt{2}\\\\=(3-6+12)\sqrt{2}\\\\ = 9\sqrt{2}$

5 0

2 years ago

2/5 divided by 8/9 I need answer right now.

Lynna [10]

Answer:.45

Step-by-step explanation:

2/5 ÷ 8/9 KCF

18/40

5 0

3 years ago

Read 2 more answers

..vertex: (4, -1)<br> f(3) = -6

s344n2d4d5 [400]

Answer:

$\huge\boxed{f(x)=-5(x-4)^2-1=-5x^2+40x-81}$

Step-by-step explanation:

The vertex form of an equation of a parabola:

$f(x)=a(x-h)^2+k$

$(h;\ k)$ - vertex

We have

vertex $(4;\ -1)\to h=4;\ k=-1$

$f(3)=-6$

Therefore we have:

$f(x)=a(x-4)^2+(-1)=a(x-4)^2-1$

Substitute $x=3$ and $f(3)=-6$

$a(3-4)^2-1=-6\qquad|\text{add 1 to both sides}\\\\a(-1)^2=-6+1\\\\a(1)=-5\\\\a=-5$

Finally:

$f(x)=-5(x-4)^2-1=-5(x^2-2(x)(4)+4^2)-1\\\\=-5(x^2-8x+16)-1=-5x^2+(-5)(-8x)+(-5)(16)-1\\\\=-5x^2+40x-80-1=-5x^2+40x-81$

4 0

4 years ago

Find the error & explain why it is wrong:

olga nikolaevna [1]

$( { \frac{4 {x}^{3} }{ {y}^{4} }) }^{ - 2} = \frac{16x {}^{6} }{ {y}^{8} }$

$\frac{(4 {x}^{3})^{ - 2} }{ { {(y}^{4} )}^{ - 2} } = \frac{16 {x}^{6} }{ {y}^{8} }$

$\frac{ {16x}^{ - 6} }{ {y }^{ - 8} } = \frac{ {16x}^{6} }{ {y}^{8} }$

The power of -2 was mistook as 2.

8 0

3 years ago