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ElenaW [278]
3 years ago
9

Read the picture that's were the question is.

Mathematics
1 answer:
vlabodo [156]3 years ago
4 0

Answer:

X is your answer bc when coordinates are flipped over the x-axis the y coordinate goes negative

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7. Write the equation of the line that is perpendicular to y = -5x + 1 and passes through the point (2,-1). slope intercept equa
Svetach [21]

Answer:

y = 1/5x - 7/5

Step-by-step explanation:

y = 1/5x + b

-1 = 1/5(2) + b

-1 = 2/5 + b

-7/5 = b

4 0
2 years ago
A triangle has sides of lengths 9,7, and 12. Is it a right triangle? Explain.
Alex Ar [27]

Answer:

A triangle has sides of lengths 9,7, and 12 is not a right triangle .

7 0
3 years ago
Write an equation of the line satisfying the given conditions. Through (2, -5), parallel to 5x 6y + 7
mojhsa [17]

We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 5x = 6y+7

When two lines are parallel, then the slopes of the two lines are equal.

Equation of line with point (x_1, y_1) and slope 'm' is given by:

(y-y_1) = m(x-x_1)

Since, we have to determine the equation of a line with point (2,-5).

So, the equation of the line is : (y-(-5)) = m(x-2)

y+5 = m(x-2)

Since, the line is parallel to the line 5x = 6y+ 7

So, 6y +7 = 5x

6y = 5x - 7

y = \frac{5}{6}x - \frac{7}{6}

So, slope of the line  'm' is \frac{5}{6}.

Therefore, the equation of the line is:

(y+5) = \frac{5}{6}(x-2)

6y + 30 = 5x - 10

6y - 5x = -10-30

6y - 5x = -40

Therefore, 6y - 5x = -40 is the required equation of the line.

8 0
2 years ago
How can you determine if information on website is relevant to your topic
GuDViN [60]
You need to look at website see what your witting about a good way to if the website has a phone number call and find on on your topic and ask questions about it
8 0
3 years ago
14x 1 =63 square root equation
soldier1979 [14.2K]
Add the one from the left to the 63 to get 64. Then divide both sides by 4 and get x^2=16. Take the square root of both sides to get x to equal 4.
4 0
3 years ago
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