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grandymaker [24]
3 years ago
14

A teacher weighed 145 lbs in 1986 and weighs 190 lbs in 2007. What is the rate of change in weight? HELP

Mathematics
2 answers:
marishachu [46]3 years ago
8 0

Answer:

c

Step-by-step explanation:

she gained 45 pounds which is 15/7 of 145

Drupady [299]3 years ago
7 0
The answer is 15/7 and here’s the explanation :)

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F(x)= -x over x^2+5 on the domain [0,4]
BartSMP [9]
If you're asking for extrema, like the previous posting

well

\bf f(x)=\cfrac{-x}{x^2+5}
\\\\\\
\cfrac{df}{dx}=\cfrac{(x^2+5)+2x^2}{(x^2+5)^2}\implies \cfrac{df}{dx}=\cfrac{5+3x^2}{(x^2+5)^2}\impliedby 
\begin{array}{llll}
using\ the\\
quotient\ rule
\end{array}

like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points

and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4

f(0) = 0        <---- only maximum, and thus absolute maximum

f(4) ≈ - 0.19  <----  only minimum, and thus absolute minimum
5 0
3 years ago
Thirty six and nine thousandths is less than greater than or equal
Gnom [1K]
36 is greater than 0.009
6 0
3 years ago
Help me out please an thank you
Aliun [14]

Answer:

The angles that are supplementary to angle 7 includes angle 5 and angle 8.

4 0
2 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
NEED WORKOUT WITH ANSWER
malfutka [58]
Answer: 81.25%
1450➗800
3 0
3 years ago
Read 2 more answers
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