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2 years ago

A teacher weighed 145 lbs in 1986 and weighs 190 lbs in 2007. What is the rate of change in weight? HELP

Mathematics

2 answers:

marishachu [46]2 years ago

8 0

Answer:

Step-by-step explanation:

she gained 45 pounds which is 15/7 of 145

Drupady [299]2 years ago

7 0

The answer is 15/7 and here’s the explanation :)

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Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

6 0

3 years ago

How do go math lesson 2.5 3rd grade?

schepotkina [342]

Send a picture of it ok then i answer

5 0

2 years ago

Read 2 more answers

Awnser please :((((((((((((((((((((

vfiekz [6]

Answer:

I believe it is: 6n+8+7y+4m

Step-by-step explanation:

You can't do anything about the numbers with variables afterwards, so you just list those and you just add and subtract the numbers without variables. Since the top and bottom are the same, you just list it once. Sorry, not the best explanation. Please let me know if I am wrong. It's been a while since I had to any type of algebra.

3 0

2 years ago

In ΔEFG, the measure of ∠G=90°, GE = 40 feet, and EF = 44 feet. Find the measure of ∠F to the nearest degree.

Licemer1 [7]

Answer:

42°

Step-by-step explanation:

It is always good to draw a picture to help you. In this case

tan F = 40/44

m∠F = arctan (40/44) = 42°

3 0

2 years ago

The average cost of a compact car at a certain dealership over the last ten years has ranged from $14,000 to $18,500. Suppose yo

mezya [45]

Answer:

Part (A): The scale of y: 1 interval being equal to 500 units and from 14,000 to 18,500.

Part (B): The good interval to use for the y-axis should be 1 to 10.

Step-by-step explanation:

Consider the provided information.

As we know the X axis represents the independent variable, since years are the independent variable. So, X axis represents the years.

Y axis represents the dependent variable, since average cost is dependent variable. So, Y axis represents the average cost.

Part (A) what is a good scale to use for the y-axis?

It is given that range is from $14,000 to $18,500.

So, 1 interval being equal to 500 units, so that it will suitable for 18,500.

The scale of y should be 14,000 to 18,500 as 14,000 is the starting average cost and 18,500 is the last average cost.

Part (b) what is a good interval to use for the y-axis?

The scale for x should be 1 year. As It should start from 1 to 10.

The good interval to use for the y-axis should be 1 to 10.

The required scale is shown in figure,

8 0

2 years ago