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Arturiano [62]
3 years ago
14

A friut stand sells watermelons during the summer. The revenue for selling x watermelons is given by f(x)=2.5x. The team's profi

t is $25 more than 60% of the revenue for selling x watermelons. Write a funcction g to model the profit. Then find the profit for selling 44 watermelons.
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

$91

Step-by-step explanation:

f(x) = 2.5 x

$25 more would + $25 to the function

60% = .6

Revenue is f(x) = 2.5x  which we have to multiply by the .6

g(x) = $25 + .6 (2.5 x)

If we have 44 watermelons then we plug in 44 for x

x = 44

g(x) = $25 + .6 (2.5*44)

g(x) = $25 + .6 (110)

g(x) = 25 + 66

g(x) = $91

The profit is $91

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Answer:

A.

Step-by-step explanation:

The x-intercepts are the points where the x value is zero. In this case, to find the "zeros" of the function, set each factor to zero. x-5 -> x=5. x-6 -> x=6. x+4 -> x=-4.

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Help me with this, Its in the doc below
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https://faq.brainly.com/hc/en-us/articles/360014661139.

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2 is the answer
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4 0
3 years ago
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0
2 years ago
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