Question

Solve the inequality 3u+3(u+1)>2u+7 and write the solution in interval notation.

Answer 1

Given:

The given inequality is $3u+3(u+1)>2u+7$

We need to determine the solution of the inequality in interval notation.

Solution of the inequality:

The solution of the inequality can be determined by simplifying the inequality.

Thus, we have,

$3u+3u+3>2u+7$

       $6u+3>2u+7$

Subtracting both sides by 3, we get;

$6 u>2 u+4$

Subtracting both sides by 2u, we have;

$4 u>4$

Dividing both sides by 4, we get;

$u>1$

Writing it in interval notation, we get;

$(1, \infty)$

Thus, the solution of the inequality is $(1, \infty)$