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Liula [17]
2 years ago
11

For Which Value of P and W is P+W a rational number. Tell me how you got that answer

Mathematics
2 answers:
Ymorist [56]2 years ago
6 0
300.02 if you use the square root of 72
vladimir2022 [97]2 years ago
5 0

Answer:

Option 2 - P=1/ square root of 4 and W=1/square root of 9                                  

Step-by-step explanation:

To find : For Which Value of P and W is P+W a rational number ?

Solution :

Solving each expression,

1) P= 1/ square root of 3 and W=1/square root of 6

i.e. P=\frac{1}{\sqrt{3}} and W=\frac{1}{\sqrt{6}}

P+W=\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{6}}

P+W=\frac{\sqrt2+1}{\sqrt{6}}

P+W=0.985598559...

It is an irrational number.

2) P=1/ square root of 4 and W=1/square root of 9

i.e. P=\frac{1}{\sqrt{4}} and W=\frac{1}{\sqrt{9}}

P+W=\frac{1}{\sqrt{4}}+\frac{1}{\sqrt{9}}

P+W=\frac{1}{2}+\frac{1}{3}

P+W=\frac{5}{6}

P+W=0.833333.....

It is a rational number as repeating decimal.

3) P=1/square root of 6 and W=1/square root of 10

i.e. P=\frac{1}{\sqrt{6}} and W=\frac{1}{\sqrt{10}}

P+W=\frac{1}{\sqrt{6}}+\frac{1}{\sqrt{10}}

P+W=\frac{\sqrt5+\sqrt3}{\sqrt{30}}

P+W=0.724476056.....

It is an irrational number.

4) P=1/square root of 25 and W=1/square root of 2

i.e. P=\frac{1}{\sqrt{25}} and W=\frac{1}{\sqrt{2}}

P+W=\frac{1}{5}+\frac{1}{\sqrt{2}}

P+W=\frac{\sqrt2+5}{5\sqrt{2}}

P+W=0.9071067811.....

It is an irrational number.

Therefore, Option 2 is correct.

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kap26 [50]

Answer:

Addition is...

1+1 = 2

But addition irrational numbers is...

π + 5 normally when using pi (π) the numbers are 3.14 but the number is infinite, all irrational numbers are infinite

then the sum will be 3.14 + 5 = 8.14

4 0
3 years ago
A chef uses 1/2 cup of cheese for a small pizza. There are 6 grams of fat in 1/4 cup of cheese. How many grams of fat are in 1/2
Elina [12.6K]

1/4 +1/4= 1/2

6g +6g= 12g

there is 12 grams of fat in 1/2 cup of cheese

4 0
3 years ago
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30                                   =-6(5)

b=-1                                          =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0
3 years ago
Round 375 to the nearest hundred
Aliun [14]
The nearest hundred would be 400
8 0
3 years ago
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RUDIKE [14]

Answer:

answer is here

Step-by-step explanation:

https://www.mathpapa.com/algebra-calculator.html

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