First distribute the 2/3.
(2/3)n + (2/3)*6 = 10
(2/3)n + 4 = 10
Subtract 4 from both sides
(2/3)n = 6
Multiply both sides by (3/2) to clear the fraction
n = 9
4 inches of rain would fall in 6 hours
<h3><u>Solution:</u></h3>
Given that, A rain storm came through Clifton park
And it was accumulating
inches of rain/hour
So amount of rain accumulated in 1 hour = ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Thus amount of rain accumulated in six hours is calculated by multiplying the amount of water accumulating per hour and 6
Amount of water accumulated in 6 hours = Amount of water accumulated in 1 hour
6
![\text { Amount of water accumaulated in 6 hours }=\frac{2}{3} \times 6=4](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Amount%20of%20water%20accumaulated%20in%206%20hours%20%7D%3D%5Cfrac%7B2%7D%7B3%7D%20%5Ctimes%206%3D4)
<em><u>Another way:</u></em>
Let "n" be the amount of rain accumulated in 6 hours
1 hour ⇒
rain accumulated
6 hours ⇒ "n"
By cross multiplication, we get
![6 \times \frac{2}{3} = 1 \times n\\\\n = \frac{2}{3} \times 6 = 4](https://tex.z-dn.net/?f=6%20%5Ctimes%20%5Cfrac%7B2%7D%7B3%7D%20%3D%201%20%5Ctimes%20n%5C%5C%5C%5Cn%20%3D%20%5Cfrac%7B2%7D%7B3%7D%20%5Ctimes%206%20%3D%204)
Hence, 4 inches of rain would fall in 6 hours.
The answer is 3/4. Hope I was able to help
Step-by-step explanation:
let y = x+5/4
Interchanging x and y , we get ;
x = y+5/4
or, 4x = y+5
or, 4x-5 = y
or, g(x) -1 = 4x-5