Total distance covered by <span>George and Carmen
</span>x + y = 350
And they biked 80 kilometers more than they bussed
<span>80 + y = x </span>
Putting the value of x=80 + y in <span>x + y = 350:
</span>We get:
<span>80 + y + y = 350 </span>
<span>2y = 270 </span>
<span>y = 135 km</span>
<span>Substituting y = 135 in x + y = 350 </span>
<span>x + 135 = 350</span>
<span>x = 215 km </span>
Thus George and Carmen biked for 215 km and bussed for 135 km.
That would be 16 because all the others are multiples of 3.
Answer:
580742.5, in words: five hundred eighty thousand seven hundred forty-two and a half.
Multiply: 1489 * 390 = 580710
Divide: 65 / 2 = 32.5
Add: 580710+32.5 = 580742.5
Answer:
7.5
Step-by-step explanation:
The relation between time, speed, and distance is ...
time = distance/speed
If distance is "1 round trip", then the time going is ...
going = 0.5/(10 mi/h) . . . . for 1/2 round trip
and the time coming is ...
coming = 0.5/(6 mi/h)
Then the average speed for the full round trip is ...
speed = distance/time
average speed = 1/(going + coming) = 1/(0.5/10 +0.5/6) mi/h
= 1/((3+5)/60) mi/h
= 60/8 mi/h = 7.5 mi/h
Jack's average speed for the round trip was 7.5 mph.
Answer:
b. 9/100
Step-by-step explanation:
It helps if you have memorized the cubes of small integers. Of course, the ones needed here are ...
3³ = 27
10³ = 1000
The desired value can be simplified to ...
![\left(-\dfrac{1000}{27}\right)^{-2/3}=\left(-\sqrt[3]{\dfrac{3^3}{10^3}}\right)^2=\dfrac{(-3)^2}{10^2}=\dfrac{9}{100}](https://tex.z-dn.net/?f=%5Cleft%28-%5Cdfrac%7B1000%7D%7B27%7D%5Cright%29%5E%7B-2%2F3%7D%3D%5Cleft%28-%5Csqrt%5B3%5D%7B%5Cdfrac%7B3%5E3%7D%7B10%5E3%7D%7D%5Cright%29%5E2%3D%5Cdfrac%7B%28-3%29%5E2%7D%7B10%5E2%7D%3D%5Cdfrac%7B9%7D%7B100%7D)
