Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61
2 answers:
Let x be first num, x+2 be second, x+4 be third
x + 4(x+4) = 61
x + 4x + 16 = 61
5x = 45
x = 9
so 9, 11, 13
Answer:
the answer would be 9, 11, 13
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Step-by-step explanation:
4×3-(-3)=12+3=15
3(2×(-3)+3)=3(-6+3)=(3×(-3)=-9
I don’t think you can do that
The parentheses must be placed here <span>48 - (5 + 2) * 3 + 6 in order for the equation to equal 33. </span>
Answer:
y=11/4x-13/4
Step-by-step explanation:
Use the slope formula and slope-intercept form y=mx+b to find the equation.
