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Leno4ka [110]
3 years ago
13

Information on a packet of seeds claims that 93% of them will germinate. Of the 200 seeds that I planted, only 175 germinated. (

a) Find a 95% CI on the true proportion of seeds that germinate based on this sample. (b) Does this seem to provide evidence that the claim is wrong
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
5 0

Answer:

We reject H₀

we accept Hₐ seeds in the packet would germinate smaller than 93%

Step-by-step explanation:

Test of proportions

One tail-test  (left side)

93 %   =  0.93

p₀  =  0,93

1.- Hypothesis

<h3>H₀            ⇒ null  hypothesis                p₀ = 0.93</h3><h3>Hₐ            ⇒ Alternative hypothesis     p  = 0.875</h3><h3>2.-Confidence interval   95 %</h3><h3>α = 0,05  </h3><h3>and </h3><h3>z(c)  =  -  1.64</h3><h3>3.- Compute z(s)</h3><h3>z(s) = (p  -  p₀)/√(p₀*q₀)/n    z(s) = (0.875-0.93)/√0.93*0.07)200</h3><h3>z(s) =  -  0,055/ √0.0003255</h3><h3>z(s) =  - 0.055/ 0.018</h3><h3>z(s) =  - 3,06</h3><h3>4.-Compere z(c)   and  z(s)</h3><h3>z(s)  <  z(c)          -3.06  <  -1.64</h3><h3>z(s)  is in rejection region, we reject H₀</h3>
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