Question

If θ is an angle in standard position and its terminal side passes through the point (-5,-6), find the exact value of

Answer 1

Answer:

$\sec \theta = -\frac{\sqrt{61}}{5}$

Step-by-step explanation:

The secant can be found by the following trigonometric relation:

$\sec \theta = \frac{1}{\cos \theta}$

$\sec \theta = \frac{1}{\frac{x}{r} }$

$\sec \theta = \frac{r}{x}$

$\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}$

$\sec \theta = \frac{\sqrt{(-5)^{2}+(-6)^{2}}}{(-5)}$

$\sec \theta = -\frac{\sqrt{61}}{5}$