Answer:
2x(2x²+x+1)
Dtep-by-step explanation:
f(x) = 9x³+2x²-5x+4
g(x) = 5x³-7x+4
f(x) - g(x)
= 9x³+2x²-5x+4 - (5x³-7x+4)
= 9x³+2x²-5x+4-5x³+7x-5
= 4x³+2x²+2x
= 2x(2x²+x+1)
Expanded Notation Form: 60,978= 60,000 +0 +900 +70 +8
Expanded Factors Form: 60,978= 6 × 10,000 +0 × 1,000 +9 × 100 +7 × 10 +8 × 1
Expanded Exponential Form: 60,978 = 6 × 104+0 × 103+9 × 102+7 × 101+8 × 100
Word Form:60,978 =sixty thousand nine hundred seventy-eight
Answer:
# of terms: 2
inConstant(s): might be wrong but i think its 5
Coefficient(s): might be y itself but i dont know
Highest degree: 5
I did what I could but this number is not factorable with rational numbers
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
5 for the first one and 7 for the second hope this helps