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Phantasy [73]
3 years ago
5

Round 1.25 to the nearest whole number

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0

Answer:

1

Step-by-step explanation:

if it's above 1.5 you would round up but it's not so

zhannawk [14.2K]3 years ago
3 0

Answer:

1

Step-by-step explanation:

1.25

The Tenth place is 2 so, 1-4 the number stays the same.

If its 5-9, number goes up

So 1.25 rounds to 1.00

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worty [1.4K]

Answer:

4

Step-by-step explanation:

 

Write an equation of a line in slope-intercept form for the given conditions.

-intercept and -intercept

(Hint: Write the intercepts as ordered pairs)

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2 years ago
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Help mee please quickkk asapp
UkoKoshka [18]

Answer:114% percent of her budget is used to entertain

Step-by-step explanation: You just add up all the money and minus it by 40%

7 0
3 years ago
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Determine if the lines are parallel, perpendicular or neither y=-3/2x-4 and y=2/3x-7
aliya0001 [1]

Answer:

<u>They are perpendicular</u>

Step-by-step explanation:

Perpendicular lines have slopes that are negated versions of the other or positive versions of the slope of the other. The slopes are also flipped.

Parallel lines have the same slope.

Neither is when the lines do not follow either of these definitions.

The slope of your two lines are -3/2 and 2/3. These slopes are flipped and the opposite negations of each other. <u>This means the lines are perpendicular.</u>

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4 0
3 years ago
Add.3/2a+5/2a PLease help!
Wittaler [7]
The answer should be 4a

4 0
3 years ago
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50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
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