Please Help!!? Leah is solving the equation using properties of exponents? 2^2x-3=(1/6)^3x+9
1 answer:
HERE IS HOW TO SOLVE:
Simplify {2}^{2}2
2
to 44
4x-3={(\frac{1}{6})}^{3}x+94x−3=(
6
1
)
3
x+9
2 Use Division Distributive Property: {(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}(
y
x
)
a
=
y
a
x
a
4x-3=\frac{1}{{6}^{3}}x+94x−3=
6
3
1
x+9
3 Simplify {6}^{3}6
3
to 216216
4x-3=\frac{1}{216}x+94x−3=
216
1
x+9
4 Simplify \frac{1}{216}x
216
1
x to \frac{x}{216}
216
x
4x-3=\frac{x}{216}+94x−3=
216
x
+9
5 Multiply both sides by 216216
864x-648=x+1944864x−648=x+1944
6 Add 648648 to both sides
864x=x+1944+648864x=x+1944+648
7 Simplify x+1944+648x+1944+648 to x+2592x+2592
864x=x+2592864x=x+2592
8 Subtract xx from both sides
864x-x=2592864x−x=2592
9 Simplify 864x-x864x−x to 863x863x
863x=2592863x=2592
10 Divide both sides by 863863
ANSWER: x= 2592 over 863
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Answer:
⇒ [Factorized form]
Step-by-step explanation:
Given expression:
We need to make the subject.
In order to do that we need to solve the expression for in terms of
and
We have,
Subtracting both sides by
Taking square root both sides in order to remove square of
The difference of squares can be factorized and written as:
[difference of squares
]