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2 years ago

Show me a graph of 6x + 5y < 30

Mathematics

1 answer:

Fittoniya [83]2 years ago

7 0

Here is a graph of <span>6x + 5y < 30</span>

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Use properties of addition and subtraction to evaluate the expression <br> -42 - 29 - 28

Setler [38]

(-42) (-29) (-28)
-42 - 29 = -71
-71 - 28 = -99

-99 is your answer

hope this helps

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3 years ago

The sale is being held from 11 a.m to 7 p.m on sunday, and from 9 a.m to 7 p.m on monday. How many hours will the sale last?

PSYCHO15rus [73]

8+10=18as your final answer

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2 years ago

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What is 3 billion divided by 24 simplified

wariber [46]

Answer: one hundred and twenty five million

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2 years ago

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What’s the multipcative inverse of 1/4

LuckyWell [14K]

Hey!

Answer:

4/1

Step-by-step explanation:

The multiplicative inverse of a number is the reciprocal of it. (a/b → b/a).

Basically you divide 1 by the other number. (1 ÷ 1/4 = 4 or 4/1).

Hope This Helps :)

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2 years ago

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Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

2 years ago

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