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adoni [48]
3 years ago
13

What is the quotient of -8a^8b^-2/10a^-4b^-10 in simplified form? Assume a=0 b=0

Mathematics
2 answers:
Alja [10]3 years ago
6 0
Are you sure that both a and b are zero?
I doubt it.

<span>-8a^8b^-2/10a^-4b^-10
should surely be written as a fraction for clarity:

</span><span>-8a^8b^-2
-----------------          (at least this is how I interpret your question)
10a^-4b^-10

-8a^8 divided by 10a^(-4) comes out to (-8/10)a^12, and

b^(-2) divided by b^(-10) comes out to b^8

so that your final quotient is (-4/5)(a^12)(b^8).</span>
valkas [14]3 years ago
4 0

Answer:

The answer is A

-4a^12b^8/5

Step-by-step explanation:

Nah

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vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

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The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

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Answer:

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y = 65*4\\y = 260

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

4 0
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