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Leokris [45]
3 years ago
6

Melissa has enough paint to cover an area of 250 square feet. She want to paint two walls. The rectangular wall is 9 feet high a

nd 20 feet wide. The square wall has a height of 9 feet. Does Melissa have enough paint to cover the area of both walls?
Mathematics
2 answers:
klasskru [66]3 years ago
8 0
Im assuming the entire room would be 9by9ft for the square walls and 20by9ft for the rectangle walls so you would do 9×9+20×9 which is 81+280= 216ft so she doesnt have enough paint
Dovator [93]3 years ago
7 0
No simply no if you multiply length times with times height you'd get 1620 ft that need to be covered if you even when with a surface area it will still not be enough to cover both walls even if you were to just paint one side of the wall it would still require more paint from.nith walls so simply no Melissa needs more paint xD
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30 points if you answer this question and please show work !!
worty [1.4K]
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5 0
3 years ago
Work out the value of (10^4)^2​
Yuri [45]

Answer:

100000000

Step-by-step explanation:

(10^4)^2                                                   key =

{(2.5)^4}^2                                                       . = times

(2^4 . 5^4)^2

(2^4) ^2 (5^4)^2

2^4 ^.2. 5^4^.2

2^8 . 5^8

256. 390625

100000000

4 0
3 years ago
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GaryK [48]

Answer:

The answers are in the attachment

7 0
2 years ago
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tiny-mole [99]

Answer:

six and one over twelve

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel
Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

x_{Sh} = x_{o} + v_{Sh}\cdot t

Submarine

x_{Su} = x_{o}+v_{Su}\cdot t

Where:

x_{o} - Position of Diego Garcia island, measured in miles.

x_{Sh}, x_{Su} - Current positions of ship and submarine, measured in miles.

v_{Sh}, v_{Su} - Velocities of ship and submarine, measured in miles per hour.

t - TIme, measured in hours.

If we know that x_{Sh} - x_{Su} = 241\,mi, v_{Sh} = 19\,\frac{mi}{h} and t = 7\,h, then:

x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t

We clear now the velocity of submarine:

\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}

v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}

v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}

v_{Su} = -15.429\,\frac{mi}{h}

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0
3 years ago
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