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larisa [96]
2 years ago
6

All movies until 4:00 pm require a discount ticket, and all movies after 4:00 PM required a regular price ticket. each theater a

t the movie Plex seats 98 people.what is the least number of showings the theater could have shown after 4:00 PM last Saturday? explain how you found your answer.

Mathematics
2 answers:
steposvetlana [31]2 years ago
8 0
Not enough info, its part c of a question that has more to go off of
alexdok [17]2 years ago
3 0

Answer:

13 showings.

Step-by-step explanation:

Using the information about the question given in the comments, we know that there are 1456 tickets sold the weekend in question.  We also know that they sold 6 times as many regular price tickets as they did discount tickets.

Let r represent regular price tickets and d represent discount tickets.  Since there were 6 times more regular price than discount, we get

r = 6d

Together, there were 1456 tickets sold:

r + d = 1456

Substitute our value from the first equation into the second:

6d + d = 1456

Combine like terms:

7d = 1456

Divide both sides by 7:

7d/7 = 1456/7

d = 208

There were 208 discount tickets sold.  This means there were 6(208) = 1248 regular price tickets sold.

The regular price tickets are sold after 4:00.  There are 98 seats in each showing; this means they needed

1248/98 = 12.7 ≈ 13 showings.

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Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

\sqrt{(x2-x1)^2 + (y2 -y1)^2}

AB = \sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}

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