Answer:
angle M and N are right angles
we can draw a line joining M and N
so we’d have a triangle MNC AND KMN
both MNC AND KMN BECOME ISOSCELES TRIANGLES
so since we have 55 degrees for angle MKN. We have to find the other 2
180-55=125
now divide by 2 to get 62.5 for each of the remaining sides of triangle KMN
now to find the sides of triangle MNC
90-62.5= 27.5
27.5*2= 55
180-55=125=angle C
(sorry, it’s complex)
I think the answer is The perimeter!
Part A:
6 2/3 *3 1/2 = 4 1/4 * x
Part B:
20/3 * 7/2 = 17/4 *x
x=20/3 * 7/2 * 4/17
x=(20*7*4) / (3*2*17)
x=560 / 102
<span>x= 5 25/51</span>
You almost had it right! remember the equation of a circle is
(x - h)^2 + (y - k)^2 = r^2. the center is (h,k) and r is the radius.
(x - 0)^2 + (y - 0)^2 = 5^2
x^2 + y^2 = 25 <<< your answer
hope that helps, God bless!
Answer:
<h2>A. -2</h2>
Step-by-step explanation:
![\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2](https://tex.z-dn.net/?f=%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3Dad-bc%5C%5C%5C%5C%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%283%29%281%29%2B%28-5%29%281%29%3D3-5%3D-2)
