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Setler79 [48]
3 years ago
5

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

+e-02n).
(a) Find the proportion of correct responses after 3 trials.
(b) Find the proportion of correct responses after 7 trials.
(c) use a graphing utility to graph the model.Find the number of trials required for the porportion of correct responses to be 0.75.
(d) Does the porportion of correct responses have a limit as n increase without bound?Explain your reasoning.

Mathematics
1 answer:
elena-s [515]3 years ago
5 0

Answer:

a)P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

b) P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

c) 0.75 =\frac{0.83}{1+e^{-0.2n}}

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

d) If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

P(n) = \frac{0.83}{1+e^{-0.2t}}

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

So the number of correct reponses  after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

0.75 =\frac{0.83}{1+e^{-0.2n}}

And we can rewrite this expression like this:

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

Now we can apply natural log on both sides and we got:

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

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Answer:

After 88 seconds, they will blink together.

Step-by-step explanation:

Time after which the first light blinks = 8 seconds

Time after which the second light blinks = 22 seconds

Initially, both the lights blink together.

To find:

The time at which they will blink together again.

Solution:

Let us have a look at the time after which each light will blink.

First light will blink after:

8 s, 16 s, 24 s, 32 s, 40 s, 48 s, 56 s, 64 s, 72 s, 80 s, <em>88 s</em>, 96 s, 104 s, ......

Second light will blink after:

22 s, 44 s, 66 s, <em>88 s</em>, 110 s, .....

It can be seen that common time is 88 second, at which the both will blink together.

So, the answer is <em>88 s.</em>

<em></em>

This answer can also be computed by taking the LCM (Least Common Multiple) of both the numbers i.e. 8 and 22.

Using the factorization method:

8=\underline{2}\times 2\times 2

22=\underline{2}\times 11

Common is 2.

Therefore the LCM will be:

2\times 2\times2\times 11 = \bold{88}

So, the answer is <em>88 s.</em>

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3 years ago
The temperature at 7pm was 45 degrees Fahrenheit. From 7pm to 11pm the temperature decreased 5 degrees each hour. Which equation
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7 0
3 years ago
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Answer:

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6 0
3 years ago
Can someone please help on both questions!! Thank you
mafiozo [28]

Question 7

<h3>Answer: A) 15</h3>

---------------------

Work Shown:

angle B = angle D = 56

angle C = angle F = 64

The missing angle A adds with B and C to get 180

A+B+C = 180

A = 180-B-C

A = 180-56-64

A = 60

Since angles B and D are congruent, and C and F are congruent, this must mean angle A = angle E. I'm using the angle angle (AA) similarity rule.

angle E = angle A

3x+15 = 60

3x = 60-15

3x = 45

x = 45/3

x = 15

Side note: I'm not sure why your teacher marked angle E as the same as angles C and F.  They should have used another angle marker to indicate that angles A and E are the same.

================================================

Question 8

<h3>Answer: B) 17</h3>

------------------------------

Work Shown:

Triangle ABC is congruent to triangle EDF. The order is important. We have A first, then B, then C for ABC. Also, we have E first, then D, then F for EDF.

Therefore, we have these three pairings

  • angle A = angle E
  • angle B = angle D
  • angle C = angle F

We'll first need angle C

A+B+C = 180

C = 180-A-B

C = 180-42-108

C = 30

which we'll then solve for x

angle F = angle C

4x-4 = 30

4x = 30+4

4x = 34

x = 34/4

x = 8.5

which doubles to

2x = 2*8.5

2x = 17

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3 years ago
What is the area of y?
Alekssandra [29.7K]
Could you draw a better graph? I can't really see where y is at or what everything is.
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