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Tomtit [17]
3 years ago
9

Holly and Tamar completed the work in the table to determine if a triangle with side lengths of 40, 42, and 58 is a right triang

le.
Mathematics
2 answers:
9966 [12]3 years ago
4 0

Answer:

The given triangle is a right angled triangle .

Step-by-step explanation:

Given : Side Lengths of Triangle are 40,42 and 58

To Find: To determine if a triangle with side lengths of 40, 42, and 58 is a right triangle.

Solution:

To check whether the given triangle is a right angled triangle or not we will use Pythagorean theorem .

Hypotenuse^{2} =Perpendicular^{2} +Base^{2}

Hypotenuse = Longest Side = 58

58^{2} =40^{2} +42^{2}

3364=1600+1764

3364=3364

Hence proved

So, the given triangle is a right angled triangle .

PIT_PIT [208]3 years ago
3 0
Simple Pythagorean theorem, And if you double check Tamara's work she is correct. Therefor B is the correct answer. 
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qaws [65]

Answer:

A I think because no matter where u start they're not symmetrical

5 0
3 years ago
If 'a' is a number lying between 0 and 1. then which of the following is in increasing order? a) a², a, √a b) a √a ,a² c) a²,√a,
viktelen [127]

Step-by-step explanation:

None of these,

a(under root),a, a(square)

this is the correct answer

5 0
3 years ago
Read 2 more answers
Find the squares of (m-1)​
Alchen [17]

Answer:

Solution

verified

Verified by Toppr

m

2

−3m−1=0

m

2

−3m=1 → (1)

Third term =(

2

1

coeeficientofm)

2

(

2

1

×(−3))

2

=(

2

−3

)

2

=

4

9

Adding

4

9

to both sides of equation (1), we get

m

2

−3m+

4

9

=1+

4

9

∴ m

2

−3m+

4

9

=

4

4+9

∴ (m−

2

3

)

2

=

4

13

Taking square roots on both sides

∴ m−

2

3

=±

2

13

∴ m=

2

3

+

2

13

or m=

2

3

−

2

13

m=

2

3+

13

,

2

3−

13

are the roots of the given quadratic equation.

8 0
2 years ago
5
AveGali [126]

Answer:

Total time taken by walking, running and cycling = 22 minutes.

Step-by-step explanation:

Let the speed of walking = x

As given,

The distance of walking = 1

Now,

As Time = \frac{Distance }{Speed}

⇒ Time traveled by walking = \frac{1}{x}

Now,

Given that - He runs twice as fast as he walks

⇒Speed of running = 2x

Also given distance traveled by running = 1

Time traveled by running = \frac{1}{2x}

Now,

Given that - he cycles one and a half times as  fast as he runs.

⇒Speed of cycling =  \frac{3}{2} (2x) = 3x

Also given distance traveled by cycling = 1

Time traveled by cycling = \frac{1}{3x}

Now,

Total time traveled = Time traveled by walking + running + cycling

                                = \frac{1}{x} +  \frac{1}{2x} + \frac{1}{3x}

                                = \frac{6+3+2}{6x} = \frac{11}{6x}

If he cycled the three mile , then total time taken = \frac{1}{3x} + \frac{1}{3x} + \frac{1}{3x} = x

Given,

He takes ten minutes longer than he would do if he cycled the three miles

⇒x + 10 = \frac{11}{6} x

⇒x - \frac{11}{6} x = -10

⇒-\frac{5}{6}x = -10

⇒x = \frac{60}{5} = 12

⇒x = 12

∴ we get

Total time traveled by walking + running + cycling = \frac{11}{6} x = \frac{11}{6} (12) = 11 (2) = 22 min

7 0
2 years ago
Pls help 10 minutes left to submit everything is on the image below
vovikov84 [41]

Answer:

a. 5

b. 1

c. 132

d. -2

Step-by-step explanation:

a. The square root of 4 is 2, the absolute value of -3 is 3. 2 + 3 = 5

b.  4 - (-3) / -7 = 7/ -7 = 1

c. 2 * 4^3 = 128 + (-3) - (-7) = 132

d. 2 (-7 + 3) = -8, square root to the third power of -8 is -2

I hope this helped, please mark Brainliest, thank you!!

6 0
3 years ago
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