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VladimirAG [237]
3 years ago
9

Alejandra made the number pattern shown below.

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0
Jnjjtyyyuuuuuuuuuuuuuuuuu
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Timmy is building a new website. Right after he starts, he has 2 visitors. He expects his visitors to increase according to a mo
Alex73 [517]

Answer:

He gets 42 visitors 4 weeks after starting to build his website.

He gets 10 new visitors per week.

Step-by-step explanation:

Equation for the number of visitors:

The equation for the number of visitors Timmy's new website receives after t weeks is:

v(t) = 10t + b

In which b is the number of visitors rightly after he starts.

Timmy is building a new website. Right after he starts, he has 2 visitors.

This means that b = 2, so:

v(t) = 10t + 2

How many visitors does he get 4 weeks after starting to build his website?

This is v(4). So

v(4) = 10(4) + 2 = 40 + 2 = 42

He gets 42 visitors 4 weeks after starting to build his website.

How any new visitors does he get per week?

After 0 weeks:

v(0) = 10(0) + 2 = 0 + 2 = 2

After 1 week:

v(1) = 10(1) + 2 = 10 + 2 = 12

2 weeks:

After 2 week:

v(2) = 10(2) + 2 = 20 + 2 = 22

22 - 12 = 12 - 2 = 10

He gets 10 new visitors per week.

5 0
3 years ago
A museum has a wax sculpture of a historical village. The scale is 1.5:8. If the height of a hut in the sculpture is 5 feet, how
Oksi-84 [34.3K]

Let us say that x is the real height of the original hut, therefore we can establish the equation:

5 : x = 1.5 : 8

5 / x = 1.5 / 8

 

Solving for x:

x = 5 * 8 / 1.5

x = 40 / 1.5

<span>x = 26.67 ft</span>

4 0
3 years ago
1. Suppose y varies directly as x. If y = 3 when x = 15. then find x when y = 5.
KATRIN_1 [288]

Answer:

when y=3,X=15

here X is five times the value of y

so now when y= 5 then the value of X will be 25

hope you understand......

8 0
4 years ago
PLS HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Vaselesa [24]

387 customers or 930 customers

8 0
4 years ago
Read 2 more answers
What is the derivative of w=(t^2+1)^100<br><br> How is it 200t(t^2+1)^99?
GuDViN [60]
(t^2+1)^100

USE CHAIN RULE

Outside first (using power rule)

100*(t^2+1)^99 * derivative of the inside

100(t^2+1)^99 * d(t^2+1)

100(t^2+1)^99 * 2t

200t(t^2+1)^99
6 0
3 years ago
Read 2 more answers
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